How to query in php whether it contains a specified array value

Query method: 1. Use the in_array() function, the syntax "in_array(value, array)", if included, return TRUE; 2. Use the array_search() function, the syntax "array_search(value, array)" , if included, returns the corresponding key name.

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

php query whether it is included Specify the array value

Method 1: Use the in_array() function

The in_array() function searches whether the specified value exists in the array. Returns TRUE if the value is found in the array, FALSE otherwise.

<?php
header("Content-type:text/html;charset=utf-8");
$people = array("Bill", "Steve", "Mark", "David");

if (in_array("23", $people, TRUE))
  {
  echo "匹配已找到<br>";
  }
else
  {
  echo "匹配未找到<br>";
  }
if (in_array("Mark",$people, TRUE))
  {
  echo "匹配已找到<br>";
  }
else
  {
  echo "匹配未找到<br>";
  }

if (in_array(23,$people, TRUE))
  {
  echo "匹配已找到<br>";
  }
else
  {
  echo "匹配未找到<br>";
  }
?>

Method 2: Use the array_search() function

array_search() function to search for a key value in the array, and Return the corresponding key name.

If the specified key value is found in the array, return the corresponding key name, otherwise return FALSE. If a key value is found more than once in the array, the key name matching the first found key value is returned.

<?php
header("Content-type:text/html;charset=utf-8");
$a = array("2", 1, "3", 4);

if (array_search(1,$a,true)){
  echo "匹配已找到<br>";
}
else{
  echo "匹配未找到<br>";
}
if (array_search("1",$a,true)){
  echo "匹配已找到<br>";
}else{
  echo "匹配未找到<br>";
}
if (array_search(5,$a,true)){
  echo "匹配已找到<br>";
}else{
  echo "匹配未找到<br>";
}
?>

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