Les fonctions des membres C peuvent-elles être partiellement spécialisées ?

Partial Specialization of Class Member Functions in C++

When working with templates in C++, you may encounter situations where you want to partially specialize a member function. However, it's important to understand that partial specialization of a member function alone is not possible.

In order to partially specialize a member function, you need to partially specialize the entire class. This is because member functions are tied to the class they belong to, and their behavior may depend on the template arguments of the class.

Consider the following example:

template <typename T, int nValue>
class Object {
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object&amp; Deform(){ 
        m_t*=nValue; 
        return *this;
    }
};

template <typename T>
Object<T,0>&amp; Object<T,0>::Deform(){
    this-&gt;m_t = -1;
    return *this;
}

If you attempt to compile this code, you will get an error stating:

PartialSpecification_MemberFu.cpp(17): error: template argument
list must match the parameter list Object<T,0>&amp; Object<T,0>::Deform().

To resolve this issue, you need to partially specialize the entire class:

template <typename T>
class Object<T, 0>
{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object&amp; Deform()
    {
        std::cout &lt;&lt; "Spec\n";
        m_t = -1;
        return *this;
    }
};

By partially specializing the class, you can now override the behavior of the Deform() function for the specific case when nValue is 0.

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