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How to serialize and deserialize JSON using ExclusionStrategy interface in Java?

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Release: 2023-08-20 21:53:24
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How to serialize and deserialize JSON using ExclusionStrategy interface in Java?

The ExclusionStrategy interface can be used to exclude any field during serialization and deserialization. We can provide a custom implementation of the ExclusionStrategy interface and register it with GsonBuilder using the setExclusionStrategies() method. It configures Gson to apply a set of exclusion policies during serialization and deserialization.

Syntax

public GsonBuilder setExclusionStrategies(ExclusionStrategy... strategies)
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Example

import com.google.gson.*;
import com.google.gson.ExclusionStrategy;
import com.google.gson.FieldAttributes;
public class ExclusionStrategyTest {
   public static void main(String args[]) throws Exception {
      <strong>Gson </strong>gson = new GsonBuilder().setExclusionStrategies(new CustomExclusionStrategy()).create();
         Person person = new Person();
         person.setFirstName("Adithya");
         person.setLastName("Sai");
         person.setAddress("Hyderabad");
         String jsonString = gson.toJson(person);
         System.out.println("Serialize a JSON: \n "+jsonString);
         String inputJson = "{\"firstName\":\"Raja\", \"lastName\":\"Ramesh\", \"address\":\"Hyderabad\"}";
         person = gson.fromJson(inputJson, Person.class);
         System.out.println("Deserialize a JSON:\n"+ person);
      }
   }
   // CustomExclusionStrategy class
class CustomExclusionStrategy implements ExclusionStrategy {
   public boolean shouldSkipField(FieldAttributes f) {
      if(f.getName().equals("firstName")) {
         return true;
      }
      return false;
   }
   public boolean shouldSkipClass(Class aClass) {
      return false;
   }
}
// Person class
class Person {
   private String firstName, lastName, address;
   public String getFirstName() {
      return firstName;
   }
   public void setFirstName(String firstName) {
      this.firstName = firstName;
   }
   public String geLastName() {
      return lastName;
   }
   public void setLastName(String lastName) {
      this.lastName = lastName;
   }
   public String getAddress() {
      return address;
   }
   public void setAddress(String address) {
      this.address = address;
   }
   public String toString() {
      return "Person [" + firstName + " " + lastName + " " + address + "]";
   }
}
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Output

Serialize a JSON:
{"lastName":"Sai","address":"Hyderabad"}
Deserialize a JSON:
Person [null Ramesh Hyderabad]
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source:tutorialspoint.com
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