Home > Backend Development > PHP Problem > How to remove the value of a specified condition from an array in php

How to remove the value of a specified condition from an array in php

青灯夜游
Release: 2023-03-16 14:32:01
Original
1971 people have browsed it

Removal steps: 1. Use the foreach statement to loop through the array, with the syntax "foreach ($array as $key => $value){//loop body statement block}"; 2. In the loop body, Use the if statement to set conditional filter elements, and use the unset() function to delete elements that meet the conditions. The syntax is "if(condition){unset($array[$key]);}".

How to remove the value of a specified condition from an array in php

The operating environment of this tutorial: windows7 system, PHP version 8.1, DELL G3 computer

php removes array designation Condition value method

In PHP, you can use the foreach and unset() functions to delete the value of the specified condition in the array.

Step 1: Use the foreach statement to loop through the array

foreach ($array as $key => $value){
    //循环体语句块
}
Copy after login

Traverse the given $array array, and assign the value of the current array to $ in each loop value, the key name is assigned to $key.

Step 2: In the loop body, use the if statement to set the conditional filter element, and use the unset() function to delete the elements that meet the condition

if(条件){
unset($array[$key]);
}
Copy after login

Example: Remove even-numbered elements from an array

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
$arr = [1,2,3,4,5,6,7,8,9,10];
echo "原数组:";
var_dump($arr);
foreach($arr as $k=>$v){
	if($v%2==0){
		unset($arr[$k]);
	}
}
echo "去除指定条件值后:";
var_dump($arr);
?>
Copy after login

How to remove the value of a specified condition from an array in php

Recommended study: "PHP Video Tutorial"

The above is the detailed content of How to remove the value of a specified condition from an array in php. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template