How to judge the level of C language input scores

Judgment method: 1. Use the "switch(score/10){case 9:A;...case 6:D;default:E;}" statement; 2. Use "if(score>= 90)A;else if(score>=80)B;...else if(score>=60)D;elseE;" statement.

The operating environment of this tutorial: windows7 system, c99 version, Dell G3 computer.

Analysis: We can either use else if to make judgments or switch case to make judgments.

The question requirements are as follows: Enter the student's score and automatically determine the grade

• Use the switch...case statement to determine the level

• Use the else if statement

1. Use the switch...case statement to determine the level

#include <stdio.h>
int main()
{
	int i;
	scanf("%d",&i);
	i/=10;
	switch(i){
		case 9:
			printf("A");
			break;
		case 8:
			printf("B");
			break;
		case 7:
			printf("C");
			break;
		case 6:
			printf("D");
			break;
		default:
			printf("E");
			break;
	}
	return 0; 
}

##2. Use if..else..if statement

#include <stdio.h>
int main()
{
	int score;
	scanf("%d",&score);
	if(score>=90)printf("A");
	else if(score>=80)printf("B");
	else if(score>=70)printf("C");
	else if(score>=60)printf("D");
	else printf("E");
	return 0; 
}

Related recommendations: "

"

The above is the detailed content of How to judge the level of C language input scores. For more information, please follow other related articles on the PHP Chinese website!