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How to catch index out of range exception in C#?

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Release: 2023-08-25 22:13:09
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How to catch index out of range exception in C#?

IndexOutOfRangeException occurs when you try to access an element whose index is outside the range of the array.

Suppose the following is our array. It has 5 elements -

int [] n = new int[5] {66, 33, 56, 23, 81};
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Now if you try to access an element with index greater than 5 then IndexOutOfRange exception will be thrown -

for (j = 0; j < 10; j++ ) {
Console.WriteLine("Element[{0}] = {1}", j, n[j]);
}
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In the above example we are trying to access the above Index 5, so the following error occurs -

System.IndexOutOfRangeException: Index is outside the range of the array.

This is the complete code -

Example

Live demonstration

using System;

namespace Demo {
   class MyArray {
      static void Main(string[] args) {
         try {
            int [] n = new int[5] {66, 33, 56, 23, 81};
            int i,j;
            // error: IndexOutOfRangeException
            for (j = 0; j < 10; j++ ) {
               Console.WriteLine("Element[{0}] = {1}", j, n[j]);
            }
            Console.ReadKey();
         } catch (System.IndexOutOfRangeException e) {
            Console.WriteLine(e);
         }
      }
   }
}
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Output

Element[0] = 66
Element[1] = 33
Element[2] = 56
Element[3] = 23
Element[4] = 81
System.IndexOutOfRangeException: Index was outside the bounds of the array.
at Demo.MyArray.Main (System.String[] args) [0x00019] in <6ff1dbe1755b407391fe21dec35d62bd>:0
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The code will produce an error-

System.IndexOutOfRangeException &minus;Index was outside the bounds of the array.
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source:tutorialspoint.com
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