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What is the method for implementing Redis distributed lock?

王林
Release: 2023-05-28 17:58:27
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    1. What is a distributed lock?

    Distributed locks are visible to multiple processes in a distributed system or cluster mode and Mutually exclusive lock.

    Implementing distributed locks based on Redis:

    1. Acquiring locks

    • Mutual exclusion: ensure that only one thread can acquire the lock;

    • Non-blocking: Try to acquire the lock, return true if successful, false if failed;

    Add lock expiration time to avoid deadlock caused by service downtime.

    SET lock thread1 NX EX 10

    2. Release lock

    • Manual release;DEL key1

    • Timeout release, add a timeout lock when acquiring the lock;

    2. Code example

    package com.guor.utils; import org.springframework.data.redis.core.StringRedisTemplate; import java.util.concurrent.TimeUnit; public class RedisLock implements ILock{ private String name; private StringRedisTemplate stringRedisTemplate; public RedisLock(String name, StringRedisTemplate stringRedisTemplate) { this.name = name; this.stringRedisTemplate = stringRedisTemplate; } private static final String KEY_PREFIX = "lock:"; @Override public boolean tryLock(long timeout) { // 获取线程唯一标识 long threadId = Thread.currentThread().getId(); // 获取锁 Boolean success = stringRedisTemplate.opsForValue() .setIfAbsent(KEY_PREFIX + name, threadId+"", timeout, TimeUnit.SECONDS); // 防止拆箱的空指针异常 return Boolean.TRUE.equals(success); } @Override public void unlock() { stringRedisTemplate.delete(KEY_PREFIX + name); } }
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    The above code exists Problem of accidental lock deletion:

    1. If thread 1 acquires the lock, but thread 1 is blocked, causing Redis to timeout and release the lock;

    2. At this time , Thread 2 tries to acquire the lock, succeeds, and executes the business;

    3. At this time, Thread 1 restarts the task and completes the execution, then releases the lock (that is, deletes the lock);

    4. However, the lock deleted by thread 1 is the same lock as the lock of thread 2. This is thedistributed lock accidental deletion problem;

    When releasing the lock, releasing the thread's own distributed lock can solve this problem.

    package com.guor.utils; import cn.hutool.core.lang.UUID; import org.springframework.data.redis.core.StringRedisTemplate; import java.util.concurrent.TimeUnit; public class RedisLock implements ILock{ private String name; private StringRedisTemplate stringRedisTemplate; public RedisLock(String name, StringRedisTemplate stringRedisTemplate) { this.name = name; this.stringRedisTemplate = stringRedisTemplate; } private static final String KEY_PREFIX = "lock:"; private static final String UUID_PREFIX = UUID.randomUUID().toString(true) + "-"; @Override public boolean tryLock(long timeout) { // 获取线程唯一标识 String threadId = UUID_PREFIX + Thread.currentThread().getId(); // 获取锁 Boolean success = stringRedisTemplate.opsForValue() .setIfAbsent(KEY_PREFIX + name, threadId, timeout, TimeUnit.SECONDS); // 防止拆箱的空指针异常 return Boolean.TRUE.equals(success); } @Override public void unlock() { // 获取线程唯一标识 String threadId = UUID_PREFIX + Thread.currentThread().getId(); // 获取锁中的标识 String id = stringRedisTemplate.opsForValue().get(KEY_PREFIX + name); // 判断标示是否一致 if(threadId.equals(id)) { // 释放锁 stringRedisTemplate.delete(KEY_PREFIX + name); } } }
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    3. The distributed lock implemented based onSETNXhas the following problems

    1. No reentrancy

    The same thread cannot be used multiple times Get the same lock.

    2. No retry

    You only try once to acquire the lock and return false. There is no retry mechanism.

    3. Timeout release

    Although timeout release of the lock can avoid deadlock, if the business execution takes a long time, it will also cause the lock to be released, posing security risks.

    4. Master-slave consistency

    If Redis is deployed in a cluster, there will be a delay in master-slave synchronization. When the host goes down, a slave will be selected as the host, but at this time There is never a lock identifier. At this time, other threads may acquire the lock, causing security issues.

    4. Redisson implements distributed locks

    Redisson is a Java memory data grid based on Redis implementation. In addition to providing commonly used distributed Java objects, it also provides many distributed services, including the implementation of various distributed locks.

    1. pom

      org.redisson redisson 3.13.6 
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    2. Configuration class

    package com.guor.config; import org.redisson.Redisson; import org.redisson.api.RedissonClient; import org.redisson.config.Config; import org.springframework.context.annotation.Bean; import org.springframework.context.annotation.Configuration; @Configuration public class RedissonConfig { @Bean public RedissonClient redissonClient(){ // 配置 Config config = new Config(); /** * 单点地址useSingleServer,集群地址useClusterServers */ config.useSingleServer().setAddress("redis://127.0.0.1:6379").setPassword("123456"); // 创建RedissonClient对象 return Redisson.create(config); } }
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    3. Test class

    package com.guor; import lombok.extern.slf4j.Slf4j; import org.junit.jupiter.api.BeforeEach; import org.junit.jupiter.api.Test; import org.redisson.api.RLock; import org.redisson.api.RedissonClient; import org.springframework.boot.test.context.SpringBootTest; import javax.annotation.Resource; import java.util.concurrent.TimeUnit; @Slf4j @SpringBootTest class RedissonTest { @Resource private RedissonClient redissonClient; private RLock lock; @BeforeEach void setUp() { // 获取指定名称的锁 lock = redissonClient.getLock("nezha"); } @Test void test() throws InterruptedException { // 尝试获取锁 boolean isLock = lock.tryLock(1L, TimeUnit.SECONDS); if (!isLock) { log.error("获取锁失败"); return; } try { log.info("哪吒最帅,哈哈哈"); } finally { // 释放锁 lock.unlock(); } } }
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    5. Explore the tryLock source code

    1 , tryLock source code

    Try to acquire the lock
    public boolean tryLock(long waitTime, long leaseTime, TimeUnit unit) throws InterruptedException { // 最大等待时间 long time = unit.toMillis(waitTime); long current = System.currentTimeMillis(); long threadId = Thread.currentThread().getId(); Long ttl = this.tryAcquire(waitTime, leaseTime, unit, threadId); if (ttl == null) { return true; } else { // 剩余等待时间 = 最大等待时间 - 获取锁失败消耗的时间 time -= System.currentTimeMillis() - current; if (time <= 0L) {// 获取锁失败 this.acquireFailed(waitTime, unit, threadId); return false; } else { // 再次尝试获取锁 current = System.currentTimeMillis(); // subscribe订阅其它释放锁的信号 RFuture subscribeFuture = this.subscribe(threadId); // 当Future在等待指定时间time内完成时,返回true if (!subscribeFuture.await(time, TimeUnit.MILLISECONDS)) { if (!subscribeFuture.cancel(false)) { subscribeFuture.onComplete((res, e) -> { if (e == null) { // 取消订阅 this.unsubscribe(subscribeFuture, threadId); } }); } this.acquireFailed(waitTime, unit, threadId); return false;// 获取锁失败 } else { try { // 剩余等待时间 = 剩余等待时间 - 获取锁失败消耗的时间 time -= System.currentTimeMillis() - current; if (time <= 0L) { this.acquireFailed(waitTime, unit, threadId); boolean var20 = false; return var20; } else { boolean var16; do { long currentTime = System.currentTimeMillis(); // 重试获取锁 ttl = this.tryAcquire(waitTime, leaseTime, unit, threadId); if (ttl == null) { var16 = true; return var16; } // 再次失败了,再看一下剩余时间 time -= System.currentTimeMillis() - currentTime; if (time <= 0L) { this.acquireFailed(waitTime, unit, threadId); var16 = false; return var16; } // 再重试获取锁 currentTime = System.currentTimeMillis(); if (ttl >= 0L && ttl < time) { // 通过信号量的方式尝试获取信号,如果等待时间内,依然没有结果,会返回false ((RedissonLockEntry)subscribeFuture.getNow()).getLatch().tryAcquire(ttl, TimeUnit.MILLISECONDS); } else { ((RedissonLockEntry)subscribeFuture.getNow()).getLatch().tryAcquire(time, TimeUnit.MILLISECONDS); } time -= System.currentTimeMillis() - currentTime; } while(time > 0L); this.acquireFailed(waitTime, unit, threadId); var16 = false; return var16; } } finally { this.unsubscribe(subscribeFuture, threadId); } } } } }
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    2. Reset the validity period of the lock

    private void scheduleExpirationRenewal(long threadId) { RedissonLock.ExpirationEntry entry = new RedissonLock.ExpirationEntry(); // this.getEntryName():锁的名字,一个锁对应一个entry // putIfAbsent:如果不存在,将锁和entry放到map里 RedissonLock.ExpirationEntry oldEntry = (RedissonLock.ExpirationEntry)EXPIRATION_RENEWAL_MAP.putIfAbsent(this.getEntryName(), entry); if (oldEntry != null) { // 同一个线程多次获取锁,相当于重入 oldEntry.addThreadId(threadId); } else { // 如果是第一次 entry.addThreadId(threadId); // 更新有效期 this.renewExpiration(); } }
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    Update the validity period, recursively call the update validity period, never expire

    private void renewExpiration() { // 从map中得到当前锁的entry RedissonLock.ExpirationEntry ee = (RedissonLock.ExpirationEntry)EXPIRATION_RENEWAL_MAP.get(this.getEntryName()); if (ee != null) { // 开启延时任务 Timeout task = this.commandExecutor.getConnectionManager().newTimeout(new TimerTask() { public void run(Timeout timeout) throws Exception { RedissonLock.ExpirationEntry ent = (RedissonLock.ExpirationEntry)RedissonLock.EXPIRATION_RENEWAL_MAP.get(RedissonLock.this.getEntryName()); if (ent != null) { // 取出线程id Long threadId = ent.getFirstThreadId(); if (threadId != null) { // 刷新有效期 RFuture future = RedissonLock.this.renewExpirationAsync(threadId); future.onComplete((res, e) -> { if (e != null) { RedissonLock.log.error("Can't update lock " + RedissonLock.this.getName() + " expiration", e); } else { if (res) { // 递归调用更新有效期,永不过期 RedissonLock.this.renewExpiration(); } } }); } } } }, this.internalLockLeaseTime / 3L, TimeUnit.MILLISECONDS);// 10S ee.setTimeout(task); } }
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    Update validity period
    protected RFuture renewExpirationAsync(long threadId) { return this.evalWriteAsync(this.getName(), LongCodec.INSTANCE, RedisCommands.EVAL_BOOLEAN, // 判断当前线程的锁是否是当前线程 "if (redis.call('hexists', KEYS[1], ARGV[2]) == 1) then // 更新有效期 redis.call('pexpire', KEYS[1], ARGV[1]); return 1; end; return 0;", Collections.singletonList(this.getName()), this.internalLockLeaseTime, this.getLockName(threadId)); }
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    3. Call lua script

     RFuture tryLockInnerAsync(long waitTime, long leaseTime, TimeUnit unit, long threadId, RedisStrictCommand command) { // 锁释放时间 this.internalLockLeaseTime = unit.toMillis(leaseTime); return this.evalWriteAsync(this.getName(), LongCodec.INSTANCE, command, // 判断锁成功 "if (redis.call('exists', KEYS[1]) == 0) then redis.call('hincrby', KEYS[1], ARGV[2], 1); // 如果不存在,记录锁标识,次数+1 redis.call('pexpire', KEYS[1], ARGV[1]); // 设置锁有效期 return nil; // 相当于Java的null end; if (redis.call('hexists', KEYS[1], ARGV[2]) == 1) then redis.call('hincrby', KEYS[1], ARGV[2], 1); // 如果存在,判断锁标识是否是自己的,次数+1 redis.call('pexpire', KEYS[1], ARGV[1]); // 设置锁有效期 return nil; end; // 判断锁失败,pttl:指定锁剩余有效期,单位毫秒,KEYS[1]:锁的名称 return redis.call('pttl', KEYS[1]);", Collections.singletonList(this.getName()), this.internalLockLeaseTime, this.getLockName(threadId)); }
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    6. Release lock unlock source code

    1. Cancel update task

    public RFuture unlockAsync(long threadId) { RPromise result = new RedissonPromise(); RFuture future = this.unlockInnerAsync(threadId); future.onComplete((opStatus, e) -> { // 取消更新任务 this.cancelExpirationRenewal(threadId); if (e != null) { result.tryFailure(e); } else if (opStatus == null) { IllegalMonitorStateException cause = new IllegalMonitorStateException("attempt to unlock lock, not locked by current thread by node id: " + this.id + " thread-id: " + threadId); result.tryFailure(cause); } else { result.trySuccess((Object)null); } }); return result; }
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    2. Delete timing Task

    void cancelExpirationRenewal(Long threadId) { // 从map中取出当前锁的定时任务entry RedissonLock.ExpirationEntry task = (RedissonLock.ExpirationEntry)EXPIRATION_RENEWAL_MAP.get(this.getEntryName()); if (task != null) { if (threadId != null) { task.removeThreadId(threadId); } // 删除定时任务 if (threadId == null || task.hasNoThreads()) { Timeout timeout = task.getTimeout(); if (timeout != null) { timeout.cancel(); } EXPIRATION_RENEWAL_MAP.remove(this.getEntryName()); } } }
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