How to convert python numbers to Chinese-Python Tutorial-php.cn

How to convert python numbers to Chinese

藏色散人

Release： 2023-01-05 16:13:53

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How to convert python numbers to Chinese: 1. Convert Arabic numerals into Chinese through the "def num_to_char(num)..." method; 2. Convert Arabic numerals into Chinese through the "def _to_chinese4(num)..." method Just convert the numbers into corresponding Chinese.

How to convert python numbers to Chinese

The operating environment of this article: windows7 system, DELL G3 computer, python3.5 version

Python realizes the conversion of Arabic numerals into Chinese

The first conversion method:

    1  -->  一
    12   -->  一二
def num_to_char(num):
    """数字转中文"""
    num=str(num)
    new_str=""
    num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"}
    listnum=list(num)
    # print(listnum)
    shu=[]
    for i in listnum:
        # print(num_dict[i])
        shu.append(num_dict[i])
    new_str="".join(shu)
    # print(new_str)
    return new_str

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The second conversion method:

     1   -->   一
    12  -->   十二
    23  -->  二十三
_MAPPING = (u&#39;零&#39;, u&#39;一&#39;, u&#39;二&#39;, u&#39;三&#39;, u&#39;四&#39;, u&#39;五&#39;, u&#39;六&#39;, u&#39;七&#39;, u&#39;八&#39;, u&#39;九&#39;, u&#39;十&#39;, u&#39;十一&#39;, u&#39;十二&#39;, u&#39;十三&#39;, u&#39;十四&#39;, u&#39;十五&#39;, u&#39;十六&#39;, u&#39;十七&#39;,u&#39;十八&#39;, u&#39;十九&#39;)
_P0 = (u&#39;&#39;, u&#39;十&#39;, u&#39;百&#39;, u&#39;千&#39;,)
_S4 = 10 ** 4
def _to_chinese4(num):
    assert (0 <= num and num < _S4)
    if num < 20:
        return _MAPPING[num]
    else:
        lst = []
        while num >= 10:
            lst.append(num % 10)
            num = num / 10
        lst.append(num)
        c = len(lst)  # 位数
        result = u&#39;&#39;
        for idx, val in enumerate(lst):
            val = int(val)
            if val != 0:
                result += _P0[idx] + _MAPPING[val]
                if idx < c - 1 and lst[idx + 1] == 0:
                    result += u&#39;零&#39;
        return result[::-1]

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