async is relatively simple to use with await. But things get a little more complicated when you try to use await inside a loop.
In this article, share some issues worth noting when using await in if loops.
For this post, let’s say you want to get the number of fruits from a fruit basket.
const fruitBasket = {
apple: 27,
grape: 0,
pear: 14
};You want to get the quantity of each fruit from fruitBasket. To get the number of fruits, you can use the getNumFruit function.
const getNumFruit = fruit => {
return fruitBasket[fruit];
};
const numApples = getNumFruit('apple');
console.log(numApples); //27Now, assuming fruitBasket is obtained from the server, here we use setTimeout to simulate.
const sleep = ms => {
return new Promise(resolve => setTimeout(resolve, ms))
};
const getNumFruie = fruit => {
return sleep(1000).then(v => fruitBasket[fruit]);
};
getNumFruit("apple").then(num => console.log(num)); // 27Finally, suppose you want to use await and getNumFruit to get the number of each fruit in an asynchronous function.
const control = async _ => {
console.log('Start')
const numApples = await getNumFruit('apple');
console.log(numApples);
const numGrapes = await getNumFruit('grape');
console.log(numGrapes);
const numPears = await getNumFruit('pear');
console.log(numPears);
console.log('End')
}First define an array to store fruits:
const fruitsToGet = [“apple”, “grape”, “pear”];
Loop Traverse this array:
const forLoop = async _ => {
console.log('Start');
for (let index = 0; index In the for loop, use getNumFruit to get the number of each fruit and print the number to the console.
Since getNumFruit returns a promise, we use await to wait for the result to be returned and print it.
const forLoop = async _ => {
console.log('start');
for (let index = 0; index When using await, you want JavaScript to pause execution until the promise returns the processing result. This means that the await in the for loop should be executed sequentially.
The results are as you would expect.
“Start”;
“Apple: 27”;
“Grape: 0”;
“Pear: 14”;
“End”;
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This behavior applies to most loops (such as while and for-of loops)…
But it cannot handle loops that require callbacks, such as forEach, map, filter, and reduce. In the next few sections, we'll examine how await affects forEach, map, and filter.
First, use forEach to traverse the array.
const forEach = _ => {
console.log('start');
fruitsToGet.forEach(fruit => {
//...
})
console.log('End')
}Next, we will try to get the number of fruits using getNumFruit. (Note the async keyword in the callback function. We need this async keyword because await is in the callback function).
const forEachLoop = _ => {
console.log('Start');
fruitsToGet.forEach(async fruit => {
const numFruit = await getNumFruit(fruit);
console.log(numFruit)
});
console.log('End')
}I expected the console to print the following:
“Start”; “27”; “0”; “14”; “End”;
But the actual result is different. Before waiting for the return result in the forEach loop, JavaScript first executes console.log('End').
The actual console print is as follows:
‘Start’ ‘End’ ‘27’ ‘0’ ‘14’
forEach in JavaScript does not support promise awareness, but also supports async and await, so await cannot be used in forEach.
If you use await in map, map always Returns an array of promise, because asynchronous functions always return promise.
const mapLoop = async _ => {
console.log('Start')
const numFruits = await fruitsToGet.map(async fruit => {
const numFruit = await getNumFruit(fruit);
return numFruit;
})
console.log(numFruits);
console.log('End')
}
“Start”;
“[Promise, Promise, Promise]”;
“End”;
If you use await in map, map always returns promises , you must wait for the promises array to be processed. Or do this via await Promise.all(arrayOfPromises).
const mapLoop = async _ => {
console.log('Start');
const promises = fruitsToGet.map(async fruit => {
const numFruit = await getNumFruit(fruit);
return numFruit;
});
const numFruits = await Promise.all(promises);
console.log(numFruits);
console.log('End')
}The running results are as follows:
If you like, you can process the return value in promise, and the parsed value will be returned value.
const mapLoop = _ => {
// ...
const promises = fruitsToGet.map(async fruit => {
const numFruit = await getNumFruit(fruit);
return numFruit + 100
})
// ...
}
“Start”;
“[127, 100, 114]”;
“End”;When you use filter, you want to filter the array with specific results. Suppose you filter an array whose number is greater than 20.
If you use filter normally (without await), as follows:
const filterLoop = _ => {
console.log('Start')
const moreThan20 = fruitsToGet.filter(async fruit => {
const numFruit = await fruitBasket[fruit]
return numFruit > 20
})
console.log(moreThan20)
console.log('END')
}Running results
Start ["apple"] END
filterawait won't work the same way. In fact, it doesn't work at all.
const filterLoop = async _ => {
console.log('Start')
const moreThan20 = await fruitsToGet.filter(async fruit => {
const numFruit = fruitBasket[fruit]
return numFruit > 20
})
console.log(moreThan20)
console.log('END')
}
// 打印结果
Start
["apple", "grape", "pear"]
ENDWhy does this happen?
When using await in a filter callback, The callback is always a promise. Since promise is always true, all items in the array pass through filter. Use the following code in filter await class
const filtered = array.filter(true);
在filter使用 await 正确的三个步骤
map返回一个promise 数组await 等待处理结果filter 对返回的结果进行处理const filterLoop = async _ => {
console.log('Start');
const promises = await fruitsToGet.map(fruit => getNumFruit(fruit));
const numFruits = await Promise.all(promises);
const moreThan20 = fruitsToGet.filter((fruit, index) => {
const numFruit = numFruits[index];
return numFruit > 20;
})
console.log(moreThan20);
console.log('End')
}如果想要计算 fruitBastet中的水果总数。 通常，你可以使用reduce循环遍历数组并将数字相加。
const reduceLoop = _ => {
console.log('Start');
const sum = fruitsToGet.reduce((sum, fruit) => {
const numFruit = fruitBasket[fruit];
return sum + numFruit;
}, 0)
console.log(sum)
console.log('End')
}运行结果：
当你在 reduce 中使用await时，结果会变得非常混乱。
const reduceLoop = async _ => {
console.log('Start');
const sum = await fruitsToGet.reduce(async (sum, fruit) => {
const numFruit = await fruitBasket[fruit];
return sum + numFruit;
}, 0)
console.log(sum)
console.log('End')
}
[object Promise]14 是什么 鬼？？
剖析这一点很有趣。
sum为0。numFruit是27(通过getNumFruit(apple)的得到的值)，0 + 27 = 27。sum是一个promise。 （为什么？因为异步函数总是返回promises！）numFruit是0.promise 无法正常添加到对象，因此JavaScript将其转换为[object Promise]字符串。 [object Promise] + 0 是object Promise] 0。sum 也是一个promise。 numFruit是14. [object Promise] + 14是[object Promise] 14。解开谜团！
这意味着，你可以在reduce回调中使用await，但是你必须记住先等待累加器！
const reduceLoop = async _ => {
console.log('Start');
const sum = await fruitsToGet.reduce(async (promisedSum, fruit) => {
const sum = await promisedSum;
const numFruit = await fruitBasket[fruit];
return sum + numFruit;
}, 0)
console.log(sum)
console.log('End')
}
但是从上图中看到的那样，await 操作都需要很长时间。 发生这种情况是因为reduceLoop需要等待每次遍历完成promisedSum。
有一种方法可以加速reduce循环，如果你在等待promisedSum之前先等待getNumFruits()，那么reduceLoop只需要一秒钟即可完成：
const reduceLoop = async _ => {
console.log('Start');
const sum = await fruitsToGet.reduce(async (promisedSum, fruit) => {
const numFruit = await fruitBasket[fruit];
const sum = await promisedSum;
return sum + numFruit;
}, 0)
console.log(sum)
console.log('End')
}
这是因为reduce可以在等待循环的下一个迭代之前触发所有三个getNumFruit promise。然而，这个方法有点令人困惑，因为你必须注意等待的顺序。
在reduce中使用wait最简单(也是最有效)的方法是
map返回一个promise 数组await 等待处理结果reduce 对返回的结果进行处理const reduceLoop = async _ => {
console.log('Start');
const promises = fruitsToGet.map(getNumFruit);
const numFruits = await Promise.all(promises);
const sum = numFruits.reduce((sum, fruit) => sum + fruit);
console.log(sum)
console.log('End')
}
这个版本易于阅读和理解，需要一秒钟来计算水果总数。
await调用，请使用for循环(或任何没有回调的循环)。forEach一起使用await，而是使用for循环(或任何没有回调的循环)。filter 和 reduce 中使用 await，如果需要，先用 map 进一步骤处理，然后在使用 filter 和 reduce 进行处理。原文地址：https://medium.com/free-code-camp/javascript-async-and-await-in-loops-30ecc5fb3939
更多编程相关知识，请访问：编程学习网站！！
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