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PHP 类初始化的时候，不能用变量参数么，怎么改呢？

WBOY
Release： 2016-06-23 14:04:52
Original
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在做 同志湾，然后遇到了问题。

我就想当函数用就够了，直接双引号没问题，换成变量就不响应。额

$entxt=$_GET["entxt"];
echo $entxt;
$x = new fanyi($entxt,1);
echo $x->go();
class fanyi
{


回复讨论(解决方案)

直接双引号没问题，换成变量就不响应。
没理解

直接双引号没问题，换成变量就不响应。
没理解
这个可以： 

<?php$entxt=$_GET["entxt"];echo $entxt;$x = new fanyi($entxt;,1);echo $x->go();class fanyi{var $cilentID;var $clientSecret;var $authUrl;var $scopeUrl;var $grantType;var $inputstring;var $toLanguage;var $fromLanguage;function __construct($inputstring,$biao='0'){
Copy after login


这个不行
$entxt=$_GET["entxt"];
echo $entxt;
$x = new fanyi("hello baby",1);
echo $x->go();
class fanyi
{
var $cilentID;
var $clientSecret;
var $authUrl;
var $scopeUrl;
var $grantType;
var $inputstring;
var $toLanguage;
var $fromLanguage;
function __construct($inputstring,$biao='0')
{

直接双引号没问题，换成变量就不响应。
没理解
说反了，上面的不行，下面的可以

new fanyi($entxt ;,1);
多了个分号，造成语法错误不能解析，而你又屏蔽了错误提示，所以没能发现这个问题

同楼上,多了个分号

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PHP 类初始化的时候，不能用变量参数么，怎么改呢？
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