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提取网址参数的正则表达式

WBOY
Release： 2016-06-13 12:10:11
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求一个提取网址参数的正则表达式

<a href='/(kwd0vo45lmdsk055xcz3ov55)/default2.aspx'>here</a>
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这部分当中的kwd0vo45lmdsk055xcz3ov55这个提取出来
我用
preg_match_all('/<a\s+href=["|\']?([^>"\' ]+)["|\']?\s*[^>]*>([^>]+)<\/a>/i',$result,$match);<br />
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不行啊
谢谢大家了
------解决思路----------------------
preg_match_all("/\((.+?)\)/i",$str, $result);<br />echo $result[1];
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Related labels：
gt match nbsp
source：php.cn
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