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php使用Zend Framework 怎么使用ajax

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Release： 2016-06-13 12:05:47
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php使用Zend Framework 如何使用ajax
我想使用ajax，可是写了半天不对 ，哪位能给个例子，或者说说代码的流程也好。感激不尽~~~~
------解决方案--------------------
用jquery最简单了
前台

<html><br /><head><br /><script language="javascript" type="text/javascript" src="jquery.min.js"></script><br /><script type="text/javascript"><br />$(function(){<br />	$('#getid').click(function(){<br />		$.ajax({<br />			url:"oo.php",<br />			success:function(res){<br />				$('#id').text(res);<br />			}<br />		})<br />	})<br />})<br /></script><br /></head><br /><body><br />ID:<label id="id">123456</label>   <a href="javascript:;" id="getid">不满意？刷新</a><br /></body><br /></html>
Copy after login

后台
<br />echo rand(0,10000);<br />
Copy after login

------解决方案--------------------
你不愿意找，那我就帮你找！
总不至于看人家是怎么做的也不愿意吧？
http://www.baidu.com/s?wd=zf+ajax&ie=utf-8
------解决方案--------------------
你用一个php页面把要用的ajax链接用php生成出来
yii为例，footer.php
<br /><script><br />var LoginUrl="<?php echo Yii::app()->createUrl('site/login');?>";<br /></script><br />
Copy after login

ajax的时候就用LoginUrl
------解决方案--------------------
AJAX的使用不会因为你使用了啥框架或者是某个开源web而有改变写法都是固定的，不知道你是想表达啥。如果是用原生js那你要写很多如果是用jquery那你就按照jquery的标准写法去写就可以了。

Related labels：
ajax gt lt nbsp script
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