Table of Contents
How It Works
Example Without Optional Chaining:
With Optional Chaining:
Common Use Cases
1. Accessing Nested Object Properties
2. Calling Methods That Might Not Exist
3. Accessing Array Elements Safely
4. With Dynamic Property Keys
Important Notes
Home Web Front-end JS Tutorial What is optional chaining (?.) in JS?

What is optional chaining (?.) in JS?

Aug 01, 2025 am 06:18 AM

Optional chaining (?.) in JavaScript safely accesses nested properties by returning undefined if any part of the chain is null or undefined, preventing runtime errors. 1. It allows safe access to deeply nested object properties, such as user.profile?.settings?.theme. 2. It enables calling methods that may not exist, like obj.someMethod?.(). 3. It supports safe array element access, e.g., users[0]?.name. 4. It works with dynamic property keys, such as user.contact?.[key]. However, it cannot be used on the left-hand side of assignments, and should be combined with nullish coalescing (??) for default values, as in user.preferences?.theme ?? 'light'. This feature is especially useful when handling incomplete or unpredictable data from APIs or configurations.

What is optional chaining (?.) in JS?

Optional chaining (?.) in JavaScript is a feature introduced in ES2020 that lets you safely access nested object properties without having to explicitly check if each reference in the chain is valid (i.e., not null or undefined).

What is optional chaining (?.) in JS?

How It Works

The ?. operator stops evaluating and returns undefined as soon as it encounters a null or undefined value in the property chain. This prevents runtime errors like "Cannot read property of undefined."

Example Without Optional Chaining:

const user = { name: "John", address: null };

// Without optional chaining, this would throw an error:
const city = user.address.city; // TypeError: Cannot read property 'city' of null

With Optional Chaining:

const city = user.address?.city; // undefined — no error
console.log(city); // Output: undefined

It only checks whether the value before ?. is null or undefined, and if so, returns undefined immediately.

What is optional chaining (?.) in JS?

Common Use Cases

1. Accessing Nested Object Properties

const user = { profile: { settings: { theme: 'dark' } } };

// Safe access
const theme = user.profile?.settings?.theme; // 'dark'
const language = user.profile?.preferences?.lang; // undefined (no error)

2. Calling Methods That Might Not Exist

const obj = {
  someMethod() {
    return "Hello";
  }
};

// Safe method call
obj.someMethod?.(); // "Hello"
obj.missingMethod?.(); // undefined — no error

3. Accessing Array Elements Safely

const users = [{ name: "Alice" }, { name: "Bob" }];

users[0]?.name; // "Alice"
users[5]?.name; // undefined — no error

4. With Dynamic Property Keys

const key = 'email';
const email = user.contact?.[key]; // Safe dynamic access

Important Notes

  • Optional chaining only works for reading/invoking. You can’t use it on the left-hand side of an assignment.
    user?.name = "John"; // ❌ SyntaxError
  • It’s not a replacement for proper data validation — it just prevents crashes during access.
  • Always pair it with fallbacks when needed:
    const theme = user.preferences?.theme ?? 'light'; // default to 'light'

    Basically, ?. makes your code safer and cleaner when dealing with uncertain object structures. It’s especially useful when working with APIs, configuration objects, or deeply nested data where some parts might be missing.

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