一个php数组转字符串的问题

Question

怎样把以下这样的数组 {代码...} 封装成 {代码...}

PHP中文网 · Answer

$array = array(
    array(
        'device_token' => 'Al9_G0i6ftf7fvkKsGM9o6jN5iyoqt8zTjcsh_kw6HUu'
    ),
    array(
        'device_token' => 'AmfUS3qeXKrJt1K1ZTICiD-ED6a_YgM3GdBRp6gR4RgV'
    )
);
$result = [];
array_walk_recursive($array, function ($value, $key) use (&$result) {
    $result[$key][] = $value;
});
foreach ($result as $key => $value) {
    $result[$key] = implode($value, ',');
}
$result = json_encode($result);
// 如果你确定你不是想要json格式的话就保留下面
$result = substr($result, 1, -1);

大家讲道理 · Answer

//php5.5

$array = array(
    array(
        'device_token' => 'Al9_G0i6ftf7fvkKsGM9o6jN5iyoqt8zTjcsh_kw6HUu'
    ),
    array(
        'device_token' => 'AmfUS3qeXKrJt1K1ZTICiD-ED6a_YgM3GdBRp6gR4RgV'
    )
);
 //如果字段不固定的话参考楼上
$result = array_column($array,'device_token');

大家讲道理 · Answer

json_encode(array) JSON

迷茫 · Answer

$out=['devices'=>''];
array_map(function($arr) use (&$out){
  $value=array_values($arr)[0];
  $out['devices'].=($out['devices'])?',':'';
  $out['devices'].=$value;
     
},$array);

print_r($out);

Array
(

[devices] => Al9_G0i6ftf7fvkKsGM9o6jN5iyoqt8zTjcsh_kw6HUu,AmfUS3qeXKrJt1K1ZTICiD-ED6a_YgM3GdBRp6gR4RgV

)