The query and formula form the entire table, with new columns, where the new columns are formulas involving other conditional column values
P粉178894235
P粉178894235 2024-04-06 21:23:40
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EDIT: The formula should be the "value" column - the "value" column with the lowest user_id based on the category.

So row 2 will be 0.04 because the "value" column of the lowest "user_id" for category "A" is 0.01.

Feel sorry.

I want to retrieve everything from the table and add another column that involves a formula containing information based on other columns. This is the original form:

category user_id value
one 1 0.01
one 2 0.05
B 4 0.34
B 7 0.27

The new column must be the minimum value "user_id" of the "value" column minus the "category" of each row. So for the second row it will be (0.05 - 1) since the category is "A" and the lowest "user_id" of "A" is 1.

There are many more rows and columns, this is just an example.

What formula would I use?

Here is what I have so far, just to be able to demonstrate that I am able to create new columns, but without the correct formula:

CREATE TABLE new_table 
 AS (select * FROM table_1);
 
 ALTER TABLE new_table
 ADD COLUMN `new_column` DECIMAL(3,2)
 GENERATED ALWAYS AS (table_1.value-table_1.value) STORED;
 
 select * from new_table;

This obviously gives me the new column, but as 0 (because it subtracts itself).

What is the correct formula?

This is the architecture:

CREATE TABLE table_1 (
  `category` VARCHAR(2),
  `user_id` INT(2), 
  `value` DECIMAL(3,2)
 );
INSERT INTO table_1
(`category`, `user_id`, `value`)
VALUES
('A', 1, 0.01),
('A', 2, 0.05),
('B', 4, 0.34),
('B', 7, 0.27)
;

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reply all(2)
P粉302160436

In mysql 5.7 you can use subquery to achieve the goal, the view seems better than the new table, but since the select is equal, you can choose

dbviolinhere p>

P粉627027031
mysql> create view new_table as 
  select category, user_id, value, 
    value - min(user_id) over (partition by category) as adjusted_value
  from table_1;

mysql> select * from new_table;
+----------+---------+-------+----------------+
| category | user_id | value | adjusted_value |
+----------+---------+-------+----------------+
| A        |       1 |  0.01 |          -0.99 |
| A        |       2 |  0.05 |          -0.95 |
| B        |       4 |  0.34 |          -3.66 |
| B        |       7 |  0.27 |          -3.73 |
+----------+---------+-------+----------------+

This uses window functions, meaning it requires MySQL 8.0, which is the current version of MySQL as of 2018.


Reply to your comment: Use the value column from the lowest user_id in the category:

mysql> create or replace view new_table as 
  select category, user_id, value, 
    value - first_value(value) over (partition by category order by user_id) as adjusted_value  
  from table_1;

mysql> select * from new_table;
+----------+---------+-------+----------------+
| category | user_id | value | adjusted_value |
+----------+---------+-------+----------------+
| A        |       1 |  0.01 |           0.00 |
| A        |       2 |  0.05 |           0.04 |
| B        |       4 |  0.34 |           0.00 |
| B        |       7 |  0.27 |          -0.07 |
+----------+---------+-------+----------------+
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