python method to split string according to fixed length

This article mainly introduces the method of splitting strings according to fixed length in python. It has certain reference value. Now I share it with you. Friends in need can refer to it.

There are a bunch of macs as follows The address needs to be changed into a certain format, such as mac='902B345FB021' to mac='90-2B-34-5F-B0-21'.
With the help of python script, it can be easily implemented. The principle is: the string is split according to a fixed length.

1, file mac.txt, saves the following mac address:

50E549E32ECB
902B3413EFA6
50E549ECBA1C
902B3457B16F
1C6F65296DF9
902B34131A14
50E549E3E2F8
50E5493A2696
902B345FB021
902B34131574

Here are two implementation methods for your reference.
Method one:

Code sample:

#!/bin/python 
#site:WWW.jb51.net
# 
A = open('mac.txt','r') 
a = A.readlines() 
for aa in a: 
 b = list(aa.strip()) 
 c='' 
 for i in range(len(b)): 
  if i !=0: 
   if i%2 == 0: 
    c=c+'-'+b[i] 
   else: 
    c=c+b[i] 
  else: 
   c=c+b[i] 
 print c 
A.close()

Method two:
Code sample:

#!/bin/python 
# 
import re 
A = open('mac.txt','r') 
a = A.readlines() 
for aa in a: 
 b=re.findall(r'.{2}',aa) 
 c='-'.join(b) 
 print c 
A.close()

It is implemented using regular expressions in python, which has high execution efficiency and is worth recommending.
Processing result:

50-E5-49-E3-2E-CB
90-2B-34-13-EF-A6
50-E5-49-EC -BA-1C
90-2B-34-57-B1-6F
1C-6F-65-29-6D-F9
90-2B-34-13-1A-14
50 -E5-49-E3-E2-F8
50-E5-49-3A-26-96
90-2B-34-5F-B0-21
90-2B-34-13-15 -74
90-2B-34-18-43-BF
00-24-1D-0E-25-8D

Python is still very good at processing strings. I recommend everyone Get a firm grip.

Python splits the string into groups of three characters according to a fixed length

def cut_text(text,lenth): 
 textArr = re.findall('.{'+str(lenth)+'}', text) 
 textArr.append(text[(len(textArr)*lenth):]) 
 return textArr 
 
print(cut_text('123456789abcdefg',3)) 
 
['123', '456', '789', 'abc', 'def', 'g']

Code 2

>>> import re
>>> string = '123456789abcdefg'
>>> re.findall(r'.{3}', string)
['123', '456', '789', 'abc', 'def']
>>>

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