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How to transform the mysql_query statement to return a class object_PHP tutorial

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Release: 2016-07-13 17:23:32
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This is a way to simplify the SQL query function. I hope it will be helpful to you
If you have a better opinion, please OICQ 86804 or EMAIL: liboys@21cn.com to study together
# SQL query
# When When count=true, only count the number of records
function db_query($query, $rec = false) {

if($rec) {
$query = explode("from", $query ); // Simple interception
$query = "select count(*) from ". $query[1];
}

$result = mysql_query($query) or die(mysql_error ());

if($rec) {
$rows = mysql_fetch_row($result);
$reccount = $rows[0];
}
else {
$reccount = mysql_num_rows($result);
}

if($reccount) {
$re->result = $result;
$re->reccount = $reccount ;
}
else {
$re = false;
}
return $re; // You can use the $re->xx method to call in the future
}

For example

...
# Just ask for the number of records
$query = "select id,name,about from table where id > 10";
$re = db_query($query,true); //Form like select count(*) from table where id > 10
print $re->reccount; //Return the number of records

#Request Query results
$query = "select id,name,about from table where id > 10";


$re=db_query($query);
for($i=0; $i reccount; $i++) {
$rows = mysql_fetch_object($re->result);
print $rows->id;
}

www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/532216.htmlTechArticleThis is a way to simplify the SQL query function. I hope it will be helpful to you. If you have a better opinion, please OICQ 86804 or EMAIL: liboys@21cn.com Let’s study together # SQL query # When count=true,...
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