php jquery ajax user login example code_PHP tutorial
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Release： 2016-07-13 10:48:44
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User login means that the user enters the user name and password, clicks on the login page without refreshing, and then uses ajax to submit it to the background program for judgment. If the login is successful, it returns true or relevant user information, thus achieving the user's no-refresh login effect.
php Jquery login without refresh, a very simple one written by myself
Added a judgment that if you are already logged in, the login status will still be displayed after refreshing
Login page file
html page
The code is as follows
代码如下
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代码如下
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session_start();
require "conn.php";
$username=$_POST['writer'];
$password=$_POST['pass'];
mysql_select_db($database_lr, $lr);
$sql="SELECT * FROM admin WHERE username='$username' AND password='$password'";
$result = mysql_query($sql);
if( mysql_num_rows($result) >0 )
{
// login sucess
$_SESSION['login_Admin']="Admin";
echo "login ok";
}
else
{
// The user ID found
echo "Login failed, ID error or expired.";
}
?>
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The code is as follows
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session_start();<🎜>
require "conn.php";<🎜>
$username=$_POST['writer'];<🎜>
$password=$_POST['pass'];<🎜>
mysql_select_db($database_lr, $lr);<🎜>
$sql="SELECT * FROM admin WHERE username='$username' AND password='$password'";<🎜>
$result = mysql_query($sql);<🎜>
if( mysql_num_rows($result) >0 )
{
// login sucess
$_SESSION['login_Admin']="Admin";
echo "login ok";
}
else
{
// The user ID found
echo "Login failed, ID error or expired.";
}
?>
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