How to pass json parameters using Post method-JS Tutorial-php.cn

How to pass json parameters using Post method

php中世界最好的语言

Release： 2018-04-20 17:23:46

Original

14448 people have browsed it

This time I will show you how to use the Post method to pass json parameters, and what are the precautions for using the Post method to pass json parameters. The following is a practical case, let's take a look.

This article mainly introduces how to use

Angularjs $http service to transfer json object data to the server using the POST method.

The details are as follows:

1. The default data type submitted by the $http POST method is application/json

var data = {'wid':'0', 'praise' : '25'}; 
$http.post(url, data).success(function(result) { 
 // 
});

Copy after login

The final request sent is:

POST http://www.example.com HTTP/1.1 
Content-Type: application/json;charset=utf-8 
 
{'wid':'0','praise':'25'}

Copy after login

The default method can directly pass the json object to the server in the form of

string, which is more suitable for RESTful interfaces. But the $_POST of the php script cannot get the json data from the request body.

You can use this:

$data = file_get_contents("php://input"); //获得原始输入流

Copy after login

Note: php://input is invalid when enctype="multipart/form-data"

After obtaining the original input stream of the request and then processing it accordingly, you can get the json data.

2. Submit the json data using x-www-form-urlencoded method

app.factory("Comment",function($http){
 return {
  get : function(commentFileUrl) {
   return $http({
    method: "GET",
    url: commentFileUrl,
    params: {R:Math.random()},
    headers: {'Cache-Control':'no-cache'}
   });
  },
  //保存一个评论
  save : function(toUrl,saveFileUrl,Data) {
   $http({
    method: "POST",
    url: toUrl,
    data: {saveUrl:saveFileUrl,commit:Data},
    headers: { 'Content-Type': 'application/x-www-form-urlencoded' },
    transformRequest: function(obj) {
     var str = [];
     for (var p in obj) {
      str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
     }
     return str.join("&");
    }
   }).success(function(data){
    console.log("数据已保存！");
   }).error(function(data) {
    alert("数据保存失败，错误信息:" + JSON.stringify({data:data}));
   });
  }
 }
});
var updateClickRate={'wid':'0','click_rate':'87'};
Comment.save("php/updateWork.php","../userdata/work_content.json",JSON.stringify(updateClickRate));

Copy after login

Finally sent request It is:

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!