指定されたリストの中央値を見つけるための C プログラム

for (i = 1 ; i <= n-1 ; i++){
   for (j = 1 ; j <= n-i ; j++){
      if (a[j] <= a[j+1]){
         t = a[j];
         a[j] = a[j+1];
         a[j+1] = t;
      } else
      continue ;
   }
}

if ( n % 2 == 0)
   median = (a[n/2] + a[n/2+1])/2.0 ;
else
   median = a[n/2 + 1];

#include<stdio.h>
#define N 10
main( ){
   int i,j,n;
   float median,a[N],t;
   printf("Enter the number of items</p><p>");
   scanf("%d", &n);
   /* Reading items into array a */
   printf("Input %d values </p><p>",n);
   for (i = 1; i <= n ; i++)
   scanf("%f", &a[i]);
   /* Sorting begins */
   for (i = 1 ; i <= n-1 ; i++){ /* Trip-i begins */
      for (j = 1 ; j <= n-i ; j++) {
         if (a[j] <= a[j+1]) { /* Interchanging values */
            t = a[j];
            a[j] = a[j+1];
            a[j+1] = t;
         }
         else
         continue ;
      }
   } /* sorting ends */
   /* calculation of median */
   if ( n % 2 == 0)
      median = (a[n/2] + a[n/2+1])/2.0 ;
   else
   median = a[n/2 + 1];
   /* Printing */
   for (i = 1 ; i <= n ; i++)
   printf("%f ", a[i]);
   printf("</p><p></p><p>Median is %f</p><p>", median);
}

Enter the number of items
5
Input 5 values
2.3
1.2
3.8
4.6
8.9
8.900000 4.600000 3.800000 2.300000 1.200000

Median is 3.800000