C プログラムで、数字 0 と 1 のみを含む数値を合計が N になるように出力します。

Input: 31
Output:10 10 10 1

int findNumbers(int n)
START
STEP 1: DECLARE AND ASSIGN VARAIBALES m = n % 10, a = n
STEP 2: LOOP WHILE a>0
   IF a/10 > 0 && a > 20 THEN,
      SUBTARCT 10 FROM a AND STORE BACK IT IN a
      PRINT "10 "
   ELSE IF a-11 == 0 THEN,
      SUBTRACT 11 FROM a AND STORE
      BACK IN a
      PRINT "11 "
   ELSE
      PRINT "1 "
      DECREMENT a BY 1
   END IF
END LOOP
STOP

#include <stdio.h>
// Function to count the numbers
int findNumbers(int n){
   int m = n % 10, a = n;
   while(a>0){
      if( a/10 > 0 && a > 20 ){
         a = a-10;
         printf("10 ");
      }
      else if(a-11 == 0 ){
         a = a-11;
         printf("11 ");
      }
      else{
         printf("1 ");
         a--;
      }
   }
}
// Driver code
int main(){
   int N = 35;
   findNumbers(N);
   return 0;
}

10 10 1 1 1 1 11