C++ で書かれており、3 つの直線上の一連の点によって形成される三角形の数を求めます。

Input: m = 3, n = 4, k = 5
Output: 205

Input: m = 2, n = 2, k = 1
Output: 10

#include <bits/stdc++.h>

#define MOD 1000000007

using namespace std;

long long fact(long long n) {
   if(n <= 1)
   return 1;
   return ((n % MOD) * (fact(n-1) % MOD)) % MOD;
}
long long comb(int n, int r) {
   return (((fact(n)) % MOD) / ((fact(r) % MOD) * (fact(n-r) % MOD)) % MOD);
}

int main() {
   int n = 3;
   int m = 4;
   int r = 5;
   long long linen = comb(n, 3); // the combination of n with 3.
   long long linem = comb(m, 3); // the combination of m with 3.
   long long liner = comb(r, 3); //the combination of r with 3.
   long long answer = comb(n + m + r, 3); // all possible comb of n, m , r with 3.
   answer -= (linen + linem + liner);
   cout << answer << "\n";
   return 0;
}

205