The example in this article describes how jqury can automatically submit a form after a few seconds. Share it with everyone for your reference. The details are as follows:
Many download websites have set up this code. The download button will count for a few seconds. After counting, you can click Submit
It’s easy to make:
1. The js part code is as follows:
<script language='javascript'>
<!--
$(document).ready(function(){
// #formDownload ajaxForm
$('#formDownload').ajaxForm({
target:'#formDownloadWindows',success:function(){
}
});
});
function jump(count,formId) {
window.setTimeout(function(){
count--;
if(count > 0) {
$('#jumpNum').html(count);
jump(count,str);
} else {
$(str).submit();
}
}, 1000);
}
//-->
</script>2. The HTML part of the code is as follows:
<form action="/action/download" method="post" id="formDownload"> Wait <span id="jumpNum"></span> seconds <input type="button" onclick="jump(30,"#formDownload");" /> </form>
I hope this article will be helpful to everyone’s jQuery programming.
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