How to sort documents and display only a single field in MongoDB 4?
To sort documents in MongoDB 4, use sort(). To display only a single sorted field, set this to 1.
Let us create a collection containing documents -
> db.demo611.insertOne({"Name":"Chris"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987110f6b89257f5584d83")
}
> db.demo611.insertOne({"Name":"Adam"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987115f6b89257f5584d84")
}
> db.demo611.insertOne({"Name":"John"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987118f6b89257f5584d85")
}
> db.demo611.insertOne({"Name":"Bob"});{
"acknowledged" : true, "insertedId" : ObjectId("5e98711bf6b89257f5584d86")
}Display all the documents in the collection with the help of find() method-
> db.demo611.find();
This will produce the following output:
{ "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" }
{ "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" }
{ "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" }
{ "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" }The following is how to sort the documents using MongoDB 4 The query -
> db.demo611.find().sort({Name:1});will produce the following output&mius;
{ "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" }
{ "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" }
{ "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" }
{ "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" }The above is the detailed content of How to sort documents and display only a single field in MongoDB 4?. For more information, please follow other related articles on the PHP Chinese website!
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