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C program to perform two halves of an operation on a single array

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Release： 2023-08-27 13:05:06

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C program to perform two halves of an operation on a single array

Question

Write a program to take a one-dimensional array of N elements and split it in half . Later, sort the first half in ascending order and the second half in descending order.

Solution

The solution of performing two operations on two halves in a single array is explained in C language as follows -

The logic of ascending sorting of the first half is as follows -

for (i=0; i<b; ++i){
   for (j=i+1; j<b; ++j){
      if (number[i] > number[j]){
         a = number[i];
         number[i] = number[j];
         number[j] = a;
      }
   }
}

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The logic used to sort the second half in descending order is as follows -

for (i=b; i<n; ++i){
   for (j=i+1; j<n; ++j){
      if (number[i] < number[j]){
         a = number[i];
         number[i] = number[j];
         number[j] = a;
      }
   }
}

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The logic used to split the array into two halves and print accordingly is as follows-

First half of ascending order

for (i=0; i<b; ++i)
printf ("%d ",number[i]);

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Second half of descending order

for(i=b;i<n;i++)
printf("%d ",number[i]);

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Example

The following is for a single array Two halves of a C program that performs two operations in -

Live Demonstration

#include<stdio.h>
void main(){
   int i,j,a,n,b,number[30];
   printf ("Enter the value of N</p><p>");
   scanf ("%d", &n);
   b = n/2;
   printf ("Enter the numbers </p><p>");
   for (i=0; i<n; ++i)
      scanf ("%d",&number[i]);
      for (i=0; i<b; ++i){
         for (j=i+1; j<b; ++j){
            if (number[i] > number[j]){
               a = number[i];
               number[i] = number[j];
               number[j] = a;
         }
      }
   }
   for (i=b; i<n; ++i){
      for (j=i+1; j<n; ++j){
         if (number[i] < number[j]){
            a = number[i];
            number[i] = number[j];
            number[j] = a;
         }
      }
   }
   printf (" The 1st half numbers</p><p>");
   printf (" arranged in asc</p><p>");
   for (i=0; i<b; ++i)
      printf ("%d ",number[i]);
   printf("</p><p>The 2nd half Numbers</p><p>");
   printf("order arranged in desc.order</p><p>");
   for(i=b;i<n;i++)
      printf("%d ",number[i]);
}

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Output

When the above program is executed, the following results are produced -

Enter the value of N

10
Enter the numbers
20
34
23
11
45
56
78
98
76
54
The 1st half numbers
arranged in asc
11 20 23 34 45
The 2nd half Numbers
order arranged in desc.order
98 78 76 56 54

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