/1 Preface/
We often check the logistics order number of the express delivery, but these logistics order numbers Where did it come from?
Express Bird integrates multiple express company query interfaces. It is very convenient and fast to enter the corresponding express company code and express delivery order number to obtain the corresponding logistics information.
##/2 Project Goals/
Teach everyone how to use Python programming to query their own logistics information.
##/3 Project preparation/
Software:PyCharm
Required library:urllib.request、json The website is as follows: ##/4 Project Analysis/ #1. Check with F12 of chrome browser, enter a courier number and click to search. As shown in the picture: 2. Find the file https://www.kuaidi100.com
1. How to get the real URL and the corresponding interface?
query?type=shentong&postid=773036432685909&temp=0.0
4、可以看到postid就是我们的快递单号,type就是各个快递公司的名字拼音的简称。那等下就可以定义这个字典去存放各个公司名字的简称拼接网址。 5、找到Preview=>>对应的data可以看到context就是物流信息。等下可以通过js解析获取对应的字段。 /5 项目实现/ 1、定义一个class类继承object。导入需要的库和网址。定义一个字典kd_dict存放快递公司简称。 /6 效果展示/ 1. Click the green triangle to run, and then enter the number of the express company representative. #2. Enter your express delivery number, and then you can see the display result on the console. As shown below. #/7 Summary/https://www.kuaidi100.com/query?type=shentong&postid=773036432685909&temp=0.03191355265516216&phone=
import urllib.request
import json
kd_dict = {1: 'shentong', 2: 'youzhengguonei', 3: 'yuantong', 4: 'shunfeng', 5: 'yunda', 6: 'zhongtong'}
class YU(object):
pass
2、建立查询框架。
while True:
print("输入要查询快递公司:")
print("1.申通 2.EMS邮政 3.圆通 4.顺风 5.韵达 6.中通 0.退出\n ")
choose = int(input("请选择您的快递公司:"))
while choose not in range(0, 7):
choose = int(input("抱歉暂不支持此公司请重新选择:"))
if choose == 0:
break
kd_num = input("请输入快递单号:")
3、对js文件进行解析。
url = "http://www.kuaidi100.com/query?type=%s&postid=%s" % (kd_dict[choose], kd_num)
response = urllib.request.urlopen(url)
html = response.read().decode('utf-8')
target = json.loads(html)
4、判断status的是不是200,是200才可以正常访问 ,获取对应的data。
if status == '200':
data = target['data']
# print(data)
data_len = len(data)
# print(data_len)
# print("\n")
5、for循环遍历,获取对应的字段。
for i in range(data_len):
print("\n时间: " + data[i]['time'])
print("状态: " + data[i]['context'] + "")
print("\n感谢使用!\n")
break
else:
print("输入有误请重新输入!\n")
6、程序循环。
while True:
YU.Check()
out = input("按任意数字退出(其他键继续).........")
if out >= '0' and out <= '7':
break
else:
print("\n")
continue
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