In web design and development, pop-up boxes are usually used to prompt or confirm some information. However, when the pop-up box stays for too long, it will affect the user experience and even produce invalid user operations. Therefore, how to make the pop-up box disappear within a few seconds is a very important issue. jQuery provides a simple solution. This article will introduce how to use jQuery to achieve a pop-up box that disappears in a few seconds.
1. Create a pop-up box
Before you start, you need to create a basic pop-up box. You can use CSS and HTML to create a simple pop-up box, as shown below:
<style> .popup{ font-size: 16px; position: fixed; left: 50%; top: 50%; transform: translate(-50%,-50%); z-index: 9999; background-color: #ffffff; border: 1px solid #dddddd; padding: 20px; } </style> <div class="popup"> 这是一个弹出框 </div>
Here, a div with a class name of popup is created, in which the basic style of the pop-up box is set. The style can be adjusted according to specific needs in actual projects.
2. Use jQuery to control the display and hiding of pop-up boxes
jQuery provides a concise method to control the display and hiding of pop-up boxes. You can use the following code to achieve this:
// 显示弹出框 $(".popup").show(); // 隐藏弹出框 $(".popup").hide();
Here, the jQuery selector is used to select the element with the class name popup, and the show() and hide() methods are used to show and hide the popup box. However, this method cannot achieve the purpose of the pop-up box disappearing automatically.
3. Use the delay function to control the pop-up box disappearing time
In order to make the pop-up box disappear within a few seconds, you can use jQuery's delay() and fadeOut() methods. You can use the following code to achieve this:
// 延迟3秒后隐藏弹出框 $(".popup").delay(3000).fadeOut();
The delay() method is used here to delay the disappearing time of the pop-up box by 3 seconds, and then the fadeOut() method is used to make the pop-up box gradually disappear within 3 seconds. This achieves the effect of making the pop-up box disappear within a few seconds.
4. Complete code implementation
Now, we have introduced how to use jQuery to achieve the effect of the pop-up box disappearing within a few seconds. The following is the complete code implementation:
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>jQuery弹出框几秒消失</title> <style> .popup{ font-size: 16px; position: fixed; left: 50%; top: 50%; transform: translate(-50%,-50%); z-index: 9999; background-color: #ffffff; border: 1px solid #dddddd; padding: 20px; } </style> <script src="https://cdn.bootcdn.net/ajax/libs/jquery/3.6.0/jquery.min.js"></script> <script> $(function(){ // 显示弹出框 $(".popup").show(); // 延迟3秒后隐藏弹出框 $(".popup").delay(3000).fadeOut(); }); </script> </head> <body> <div class="popup"> 这是一个弹出框 </div> </body> </html>
Here, use the jQuery selector to select the element with the class name popup, then display the popup box after the page is loaded, and then use the delay() and fadeOut() methods to realize the popup. The effect of the frame disappearing after 3 seconds.
Summary
This article introduces how to use jQuery to achieve the effect of the pop-up box disappearing within a few seconds. First, you need to create a basic pop-up box, and then use jQuery's selector and show() , hide(), delay(), fadeOut() and other functions to control the display and hiding of the pop-up box, and finally achieve the effect of the pop-up box disappearing within a few seconds. Hope this article is helpful to beginners.
The above is the detailed content of jquery popup box disappears in a few seconds. For more information, please follow other related articles on the PHP Chinese website!