sqlserver树状结构表中,获取指定节点的所有父节点路径

sqlserver树状结构表中,获取指定节点的所有父节点路径_MySQL

WBOY

Release： 2016-05-30 17:09:49

Original

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CREATE PROCEDURE [dbo].[A_P_GetParentIds]
    (
      @IdValue NVARCHAR(36) ,-- 子节点值
      @tableName NVARCHAR(MAX) ,-- 表名
      @ParentIdColumnName NVARCHAR(MAX) ,-- 父节点列名
      @ChildIdColumnName NVARCHAR(MAX)-- 子节点列名
	)
AS
    DECLARE @sqlTemp NVARCHAR(MAX); --查询sql
    SET @sqlTemp = &#39; with cte_root as
(
 select &#39; + @ParentIdColumnName + &#39; from &#39; + @tableName + &#39; where &#39;
        + @ChildIdColumnName + &#39; = &#39;&#39;&#39; + @IdValue + &#39;&#39;&#39; union all
  select a.&#39; + @ParentIdColumnName + &#39; from &#39; + @tableName
        + &#39; a inner join cte_root b on a.&#39; + @ChildIdColumnName + &#39;=b.&#39;
        + @ParentIdColumnName + &#39; ) &#39; + CHAR(10) + &#39;select * from cte_root &#39;; 

------返回查询结果-----
    EXEC sp_executesql @sqlTemp;


GO

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CREATE PROCEDURE [dbo].[A_P_GetParentInfo]
    (
      @IdValue NVARCHAR(36) ,-- 子节点值
      @tableName NVARCHAR(MAX) ,-- 表名
      @ParentIdColumnName NVARCHAR(MAX) ,-- 父节点列名
      @ChildIdColumnName NVARCHAR(MAX)-- 子节点列名
	)
AS
    DECLARE @sqlTemp NVARCHAR(MAX); --查询sql
    SET @sqlTemp = &#39; with cte_root as
(
 select *  from &#39; + @tableName + &#39; where &#39;
        + @ChildIdColumnName + &#39; = &#39;&#39;&#39; + @IdValue + &#39;&#39;&#39; union all
  select a.*  from &#39; + @tableName
        + &#39; a inner join cte_root b on a.&#39; + @ChildIdColumnName + &#39;=b.&#39;
        + @ParentIdColumnName + &#39; ) &#39; + CHAR(10) + &#39;select * from cte_root &#39;; 

------返回查询结果-----
    EXEC sp_executesql @sqlTemp;

GO

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调用测试：

DECLARE	@return_value int

EXEC	@return_value = [dbo].[A_P_GetParentIds]
		@IdValue = N&#39;a29672f9-3d03-4cfc-9cb0-403ce729db5b&#39;,--子节点值
		@tableName = N&#39;SystemMenu&#39;,--表名
		@ParentIdColumnName = N&#39;ParentId&#39;,--父节点列名
		@ChildIdColumnName = N&#39;Id&#39;--子节点列名

SELECT	&#39;Return Value&#39; = @return_value

GO

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