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How to return json in php

藏色散人
Release: 2023-03-17 06:18:01
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php返回json的方法:1、在php文件中设置“header('Content-Type:application/json; charset=utf-8');”;2、创建“array('a'=>1,'b'=>2);”;3、通过“exit(json_encode($data));”返回json数据即可。

How to return json in php

本教程操作环境:windows7系统、PHP8.1版、DELL G3电脑

PHP如何返回json数据?

php返回json,xml,JSONP等格式的数据

1、返回json数据:

header('Content-Type:application/json; charset=utf-8');
$arr = array('a'=>1,'b'=>2);
exit(json_encode($data));
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注意:如果不加header直接输出json_encode的值的话,返回的是字符串不是对象,js那边就需要先eval('('+data+')')转化为对象,再取值。

2、返回xml数据:   

header('Content-Type:text/xml; charset=utf-8');
exit($xml);
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3、返回jsonp数据:

$arr = array('a'=>1, 'b'=>2, 'c'=>3);
$json = json_encode($arr);
$callback = $_GET['callback'];
exit($callback."($json)");
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// 注意callback是js传过来的参数名称

thinkphp如何返回各种数据:

$this->ajaxReturn (json_encode($arr),'JSON');
$this->ajaxReturn (json_encode($arr),'JSONP');
$this->ajaxReturn (json_encode($arr),'XML');
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json_encode有个参数禁止unicode编码

JSON_UNESCAPED_UNICODE

json_encode('中文',JSON_UNESCAPED_UNICODE);
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默认中文编码

header('Content-Type:application/json; charset=gbk');

$data = $db->select($sql);
$data = json_encode($data);
$data=preg_replace("#\\\u([0-9a-f]{4})#ie", "iconv('UCS-2BE', 'gbk', pack('H4', '\\1'))", $data);

exit($data);
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长度用count()

$sjson = json_decode($res);  
for($i=0;$i<count($sjson);$i++)
{ 
    echo $sjson[$i];
}
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