How to use the apply() method in jquery

In jquery, the apply() method is used to change the this pointer and replace the current object with another object. It is a method of applying a certain object. The syntax is "apply(thisobj,[argarray])"; The parameter argarray indicates that it is passed in the form of an array.

The operating environment of this tutorial: windows10 system, jquery3.2.1 version, Dell G3 computer.

How to use the apply() method in jquery

The call() method and the apply() method have the same effect: change the this pointer.

Specific syntax:

apply(thisobj,[argarray])

The apply() method and the call() method have similar functions. The difference lies in the parameter transfer form. The apply() method has only two parameters. The thisobj parameter is the same as the call() parameter. The usage in the call() method is the same. The second parameter argarray is passed in the form of an array. This is different from call(). In addition to thisobj, call() can pass multiple separate parameters.

The two methods are slightly different in the organization of parameters, but have similar functions.

The calling object of the call method is generally a function, and the function itself is also an object.

The first parameter thisobj is the new context of the function object. Depending on the thisobj object, the execution context of the function may be different. If the thisobj parameter is not passed, the default context is the global window.

Examples are as follows:

For example:

add.call() does not pass in the thisobj parameter, this in function add points to window, and the output result is 2.

add.call(s,3,1), when the thisobj parameter is passed into s, this in function add points to s, so the output result is 6.

function add(c, d){
    return this.a + this.b + c + d;
}
var o = {a:1, b:3};
add.call(o, 5, 7); // 1 + 3 + 5 + 7 = 16  this指向o
add.apply(o, [10, 20]); // 1 + 3 + 10 + 20 = 34  this指向o

Related video tutorial recommendations: jQuery Video tutorial

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