Given an array A of integers sorted in non-decreasing order, return a new array consisting of the square of each number, which is also required to be sorted in non-decreasing order. Today, the editor will introduce the method of realizing the square of ordered array in PHP. You can refer to it if you need it.
Given an array A of integers sorted in non-decreasing order, return a new array consisting of the square of each number, also sorted in non-decreasing order.
Example 1:
输入:[-4,-1,0,3,10] 输出:[0,1,9,16,100]
Example 2:
输入:[-7,-3,2,3,11] 输出:[4,9,9,49,121]
Solution idea 1
Built-in function solution
Code
class Solution { /** * @param Integer[] $A * @return Integer[] */ function sortedSquares($A) { foreach ($A as &$item) { $item = $item * $item; } sort($A); return $A; }}
Solution idea 2
Double pointer traversal, and with the help of the new array, after calculating the square The results are placed in the new array from large to small.
class Solution { /** * * * 2 为自乘 2 次,也是平方 * @param Integer[] $A * @return Integer[] */ function sortedSquares($A) { $ans = []; $i = 0; $j = count($A) - 1; $k = count($A) - 1; while ($i <= $j) { // 原数组是有序的,所以 -$A[$i] > $A[$j] 即为 $A[$i] 的绝对值平方后更大 if (-$A[$i] > $A[$j]) { $ans[$k--] = $A[$i] ** 2; // 左指针向右移动 $i++; } else { $ans[$k--] = $A[$j] ** 2; $j--; } } return $ans; }}
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