Home > Backend Development > PHP Problem > How to implement video upload in php

How to implement video upload in php

藏色散人
Release: 2023-03-04 10:58:02
Original
5535 people have browsed it

How to upload video in php: first open the "php.ini" configuration file and modify the relevant parameters; then use "XHR2" to cut and upload the file; then move the video file to the desired location ;Finally add the video to the database.

How to implement video upload in php

Recommended: "PHP Video Tutorial"

php video upload is super simple

First of all, because videos are generally relatively large, we have to modify the PHP configuration first: here are two methods:

Method 1: Open: php.ini

Modify the upload configuration inside, find the following parameters, and modify them in order

file_uploads = On
  upload_tmp_dir = "d:/fileuploadtmp"
  upload_max_filesize = 50M
  post_max_size = 100M
  max_execution_time = 600
  max_input_time = 600
  memory_limit = 128M
Copy after login

Method 2: Use php functions to modify

ini_get() to get php .ini setting value

ini_set() sets php.ini

Suppose you want to upload a large file of 50M. Configure php.ini as follows:

file_uploads = On
 upload_tmp_dir = "d:/fileuploadtmp"
 upload_max_filesize = 50M
 post_max_size = 100M
 max_execution_time = 600
 max_input_time = 600
 memory_limit = 128M
Copy after login

Tips: You need to keep memory_limit > post_max_size > upload_max_filesize

::::::::::::: :Universal dividing line:::::::::::::::::::::::::::::::::::::::::::::::::::::::

Assumption: The video file is too large, we must cut it

Use XHR2 to realize cutting and uploading files

The specific code is as follows:

var fileobj = document.getElementByTagName('input')[i].files[0];//获取文件上传对象的文件资源
const SLICESIZE = 10 * 1024 * 1024;//每次切割的大小,这里是10MB//此处可做修改
var start = 0;   //初始化截取开始位置
var end = 0;   //初始化截取终止位置
totalsize = fileobj.size; //获取文件的总的大小
while(start < totalsize){ //利用while循环将文件进行截取提交
start = end ; //
end = start + SLICESIZE; //
 
var xhr = new XMLHttpRequest(); //创建ajax对象
 
var fd = new FormData(); //创建表单对象
 
var part = fileobj.slice(start,end);//对文件进行切割,两个参数
 
fd.append(&#39;name&#39;,part);//把切割文件打包进表单对象中以便发送,其中name的值就是服务器$_FILES[&#39;name&#39;]接受处的变量名
xhr.open(&#39;POST&#39;,&#39;test.php&#39;,false);//之所以关闭异步,是为了防止文件块送达服务器的顺序出错
 
xhr.send(fd);//把打包的数据发送
}
Copy after login

Go to the php page and start receiving the value

At this time, the video file is transferred to upload/data/videp/demo.mov;

Next, let’s talk about this Move the file to the location you want

Because I always failed to use move_uploaded_file (you can try it), I was wondering if I could rename this temporary file.

I Try to use rename

to store the video into the database

To display it in the foreground, use

{if $brand_video}
     <embed src="http://www.ecshop.com/data/video/{$brand_video}" sutostart=true loop=true width=800 height=600></embed>
{/if}
Copy after login

Parameter analysis: sutostart::Whether to play automatically

Loop:: Whether to loop or not

I won’t say anything about the width and height, everyone knows it.

The above is the detailed content of How to implement video upload in php. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template