The content of this article is about how PHP can count the number of times a number appears in a sorted array (code). It has certain reference value. Friends in need can refer to it. I hope it will be helpful to you. help.
Count the number of times a number appears in the sorted array.
1. Ordered array search, use binary method
2. Binary method to find the position of the first occurrence, binary method to find the position of the last occurrence, end - start 1
left=getLeft(data,k) right=getRight(data,k) retun right-left+1 getLeft data,k left=0 right=arr.length-1 mid=left+(right-left)/2 while left<=right if arr[mid]<k //关键 left=mid+1 else right=mid-1 mid=left+(right-left)/2 return left getRight data,k left=0 right=arr.length-1 mid=left+(right-left)/2 while left<=right if arr[mid]<=k //关键 left=mid+1 else right=mid-1 mid=left+(right-left)/2 return right
<?php function GetNumberOfK($data, $k) { $left=getLeft($data,$k); $right=getRight($data,$k); return $right-$left+1; } function getLeft($arr,$k){ $left=0; $right=count($arr)-1; $mid=intval($left+($right-$left)/2); while($left<=$right){ if($arr[$mid]>=$k){//关键 $right=$mid-1; }else{ $left=$mid+1; } $mid=intval($left+($right-$left)/2); } return $left; } function getRight($arr,$k){ $left=0; $right=count($arr)-1; $mid=intval($left+($right-$left)/2); while($left<=$right){ if($arr[$mid]<=$k){//关键 $left=$mid+1; }else{ $right=$mid-1; } $mid=intval($left+($right-$left)/2); } return $right; } $arr=array(1,2,3,4,4,4,5); $m=GetNumberOfK($arr,4); var_dump($m);
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