Several methods to remove duplicates from lists in python

This article mainly introduces various methods of deduplicating lists in Python. Now I share it with you. Friends who need it can refer to it.

I encountered a problem today. After a casual prompt from a colleague, The itertools.groupby function is used. However, this thing was not used in the end.

The problem is to deduplicate the news IDs in a list, and ensure that the order remains unchanged after deduplication.

Intuitive method

The simplest idea is:

Copy code Code As follows:

ids = [1,2,3,3,4,2,3,4,5,6,1]
news_ids = []
for id in ids:
    if id not in news_ids:
        news_ids.append(id)
print news_ids

This is also possible, but it doesn’t look cool enough.

Use set

Another solution is to use set:

##Copy the code The code is as follows:

ids = [1,4,3,3,4,2,3,4,5,6,1]
ids = list(set(ids))

The result is that the original order is not maintained.

Sort again according to index

Copy code The code is as follows:

ids = [1,4,3,3,4,2,3,4,5,6,1]
news_ids = list(set(ids))
news_ids.sort(ids.index)

Using itertools.grouby

Copy code The code is as follows:

ids = [1,4,3,3,4,2,3,4,5,6,1]
ids.sort()
it = itertools.groupby(ids)
for k, g in it:
    print k

Netizen added: Use reduce

Copy code The code is as follows:

In [5]: ids = [1,4,3,3,4,2,3,4,5,6,1]
In [6]: func = lambda x,y:x if y in x else x + [y]
In [7]: reduce(func, [[], ] + ids)
Out[7]: [1, 4, 3, 2, 5, 6]

The above is the code I run in ipython, in which the lambda x,y:x if y in x else x [y] is equivalent to lambda x,y: y in x and x or x [y] .

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