Home > Backend Development > PHP Tutorial > Why can't the following json be converted into an array normally?

Why can't the following json be converted into an array normally?

WBOY
Release: 2016-09-05 08:59:53
Original
1217 people have browsed it

[{id:'150',cnname:'Fuzhou City'},{id:'151',cnname:'Xiamen City'},{id:'152',cnname:'Putian City'},{id: '153',cnname:'Sanming City'},{id:'154',cnname:'Quanzhou City'},{id:'155',cnname:'Zhangzhou City'},{id:'156',cnname :'Nanping City'},{id:'157',cnname:'Longyan City'},{id:'158',cnname:'Ningde City'}]

Is it a format problem? I include all fields in single quotes, or is json_decode($str_json, 1); unable to be converted into an array

Reply content:

[{id:'150',cnname:'Fuzhou City'},{id:'151',cnname:'Xiamen City'},{id:'152',cnname:'Putian City'},{id: '153',cnname:'Sanming City'},{id:'154',cnname:'Quanzhou City'},{id:'155',cnname:'Zhangzhou City'},{id:'156',cnname :'Nanping City'},{id:'157',cnname:'Longyan City'},{id:'158',cnname:'Ningde City'}]

Is it a format problem? I include all fields in single quotes, or is json_decode($str_json, 1); unable to be converted into an array

Look at the syntax definition of JSON, and you will find that there are actually no single quotes in JSON syntax, only double quotes, and all keys are represented by strings, which means they must be quoted.

Your content is a legal JS array representation, but it is not in JSON format.

<code class="json">[
  {
    "id": "150",
    "cnname": "福州市"
  },
  {
    "id": "151",
    "cnname": "厦门市"
  },
  {
    "id": "152",
    "cnname": "莆田市"
  },
  {
    "id": "153",
    "cnname": "三明市"
  },
  {
    "id": "154",
    "cnname": "泉州市"
  },
  {
    "id": "155",
    "cnname": "漳州市"
  },
  {
    "id": "156",
    "cnname": "南平市"
  },
  {
    "id": "157",
    "cnname": "龙岩市"
  },
  {
    "id": "158",
    "cnname": "宁德市"
  }
]</code>
Copy after login
Related labels:
php
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template