This can display a picture, but what should I do if I want to display all the pictures in the img folder? It doesn't work if I change it to $url = 'upload/'; So what should I do?
<code>header("Content-Type: image/jpeg;text/html; charset=utf-8");
$url='1.jpg';
$img = file_get_contents($url,true);
echo $img;</code>This can display a picture, but what should I do if I want to display all the pictures in the img folder? It doesn't work if I change it to $url = 'upload/'; So what should I do?
<code>header("Content-Type: image/jpeg;text/html; charset=utf-8");
$url='1.jpg';
$img = file_get_contents($url,true);
echo $img;</code>
There are many methods, examples are as follows
<code>$dir = "upload/"; //要获取的目录
if (is_dir($dir)){
if ($dh = opendir($dir)){
while (($file = readdir($dh))!= false){
$filePath = $dir.$file;
echo "<img src='".$filePath."'/>";
}
closedir($dh);
}
}</code>
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