How to solve php exception parse error: syntax error, unexpected t

How to solve php exception parse error: syntax error, unexpected t_var error

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Release： 2016-07-25 09:12:46

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In PHP, variables do not need to be declared with var, but when a variable is used as a member variable of a class, there is still no problem using var.

Actually, this is a very easy problem to solve. In my opinion, it seems familiar, haha, I recently learned javascript but learned to use var to declare variables. In fact, there is no need to use var declaration in PHP, but when a variable is used as a member variable of a class, there is still no problem in using var. When using var externally, an error occurs: parse error: syntax error, unexpected t_var in..., for example, my error message: parse error: syntax error, unexpected t_var in d:apache2.2htdocsshirdrnpagep2pageutil.inc on line 34

Test: An error occurred when using a self-defined class object as a member of the class inside a class. 1. The address.inc code corresponding to the address class:

class address {
var $road;
function address(){}
function setroad($road){
$this->road = $road;
}
}
?>

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2, person class and test code are person.php:

require("address.inc");
class person {
var $name;
var $address;
function person(){
}
function display(){
echo "name : ".$this->name."
";
echo "road : ".$this->address->road."
";
}
}
var $p = new person();
$p->address = new address();
$p->address->setroad("chagnchun road");
$p->name = "shirdrn" ;
$p->display();
?>

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The test output is abnormal: parse error: syntax error, unexpected t_var in d:apache2.2htdocsshirdrnpagep2pageutil.inc on line 34 Because var is used to declare variables in the person.php code, this cannot be done in PHP. As long as the "$" symbol is used at the beginning, it means that what follows this character is a PHP variable.

Supplementary methods: Problem solved: syntax error, unexpected t_string, expecting t_old_function or t_function or t_var or I started my own PHP journey two days ago and made a very ordinary website. It turns out that our PHP is version 5.0 and the server is version 4.0. I am so confused.

Solution: parse error: syntax error, unexpected t_string, expecting t_old_function or t_function or t_var or '}', if there is "public", remove "public". There will be no error. If "public" is a defined variable, change "public" to "var".