Code sharing for php to read image content and output it to the browser

WBOY
Release: 2016-07-25 08:57:11
Original
1208 people have browsed it
This article introduces how to use PHP to read images and output it to a piece of code displayed by the browser. Friends in need can refer to it.

In php, if php outputs pictures, zip, exe and other files to the browser, and other characters are output in front, garbled characters will appear. Cause Analysis: It is caused by spaces or other characters being output before the output image. Please check whether there are other characters before the output image. If it is UTF-8 encoding, remember to save it as a BOM-free file.

Example:

<?php
//输出图片内容到浏览器
//by bbs.it-home.org
class imgdata{
 public $imgsrc;
 public $imgdata;
 public $imgform;
 public function getdir($source){
  $this->imgsrc  = $source;
 }
 public function img2data(){
  $this->_imgfrom($this->imgsrc);
  return $this->imgdata=fread(fopen($this->imgsrc,'rb'),filesize($this->imgsrc));
 }
 public function data2img(){
  header("content-type:$this->imgform");
  echo $this->imgdata;
  //echo $this->imgform;
  //imagecreatefromstring($this->imgdata);
 }
 public function _imgfrom($imgsrc){
  $info=getimagesize($imgsrc);
  //var_dump($info);
  return $this->imgform = $info['mime'];
 }
}
$n = new imgdata;
$n -> getdir("1.jpg");
$n -> img2data();
$n -> data2img();
?>
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Attached, extract an image file and display it on the browser, code:

<?php
$size = getimagesize($filename); //获取mime信息
$fp=fopen($filename, "rb"); //二进制方式打开文件
if ($size && $fp) {
header("Content-type: {$size['mime']}");
fpassthru($fp); // 输出至浏览器
exit;
} else {
// error
}
?>
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source:php.cn
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