Home > Backend Development > PHP Tutorial > php使用fsockopen函数发送post,get请求获取网页内容的方法_php技巧

php使用fsockopen函数发送post,get请求获取网页内容的方法_php技巧

WBOY
Release: 2016-05-16 20:31:49
Original
1100 people have browsed it

本文实例讲述了php使用fsockopen函数发送post,get请求获取网页内容的方法。分享给大家供大家参考。

具体实现代码如下:

复制代码 代码如下:
$post =1;
$url = parse_url($url);
$host ='http://www.jb51.net';
$path ='/';
$query ='?action=phpfensi.com';
$port =80;
 
if($post) {
  $out = "post $path http/1.0 ";
  $out .= "accept: */* ";
  //$out .= "referer: $boardurl ";
  $out .= "accept-language: zh-cn ";
  $out .= "content-type: application/x-www-form-urlencoded ";
  $out .= "user-agent: $_server[http_user_agent] ";
  $out .= "host: $host ";
  $out .= 'content-length: '.strlen($post)." ";
  $out .= "connection: close ";
  $out .= "cache-control: no-cache ";
  $out .= "cookie: $cookie ";
  $out .= $post;
 } else {
  $out = "get $path http/1.0 ";
  $out .= "accept: */* ";
  //$out .= "referer: $boardurl ";
  $out .= "accept-language: zh-cn ";
  $out .= "user-agent: $_server[http_user_agent] ";
  $out .= "host: $host ";
  $out .= "connection: close ";
  $out .= "cookie: $cookie ";
 }
 $fp = @fsockopen(($ip ? $ip : $host), $port, $errno, $errstr, $timeout);
 if(!$fp) 
 {
  return '';//note $errstr : $errno 
 } else {
  return '成功访问';
 }

fsockopen语法:
复制代码 代码如下:
resource fsockopen(string $hostname [,int $port = -1 [, int &$errno [,string &$errstr [, float $timeout = ini_get("default_socket_timeout") ]]]] )

启动一个套接字连接到指定的主机的资源,php支持在互联网领域的目标和unix在所支持的套接字传输列表说明,所支持的传输列表也可以检索使用stream_get_transports().

该插座预设会被启用,阻塞模式,你可以切换到非阻塞模式使用stream_set_blocking(),如果上面实例看不懂,就来看个简的吧,代码如下:

复制代码 代码如下:
$fp = fsockopen("www.jb51.net", 80, $errno, $errstr, 30);
 if (!$fp) {
  echo "$errstr ($errno) ";
 } else {
  $out = "get / http/1.1 ";
  $out .= "host: www.jb51.net";
  $out .= "connection: close ";
  fwrite($fp, $out);
  while (!feof($fp)) {
   echo fgets($fp, 128);
  }
  fclose($fp);
 }

希望本文所述对大家的PHP程序设计有所帮助。

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template