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PHP CURL simulates POST to submit XML data_PHP tutorial

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Release: 2016-07-20 11:11:48
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This article will introduce to you a way to use PHP CURL to simulate POST to submit XML data. Because the recipient only accepts xml data, I wrote one. I will share it with friends below. Friends in need can refer to it.

The code is as follows
 代码如下 复制代码


$url = "http://www.bkjia.com/ login";
 
 $ch = curl_init();
$header[] = "Content-type: text/xml";//定义content-type为xml
curl_setopt($ch, CURLOPT_URL, $url); //定义表单提交地址
curl_setopt($ch, CURLOPT_POST, 1);   //定义提交类型 1:POST ;0:GET
curl_setopt($ch, CURLOPT_HEADER, 1); //定义是否显示状态头 1:显示 ; 0:不显示
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);//定义请求类型
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 0);//定义是否直接输出返回流
curl_setopt($ch, CURLOPT_POSTFIELDS, $data); //定义提交的数据,这里是XML文件
 curl_close($ch);//关闭

Copy code

 代码如下 复制代码

//首先要引用这个类
include("/data/tools/pooy/Snoopy/Snoopy.class.php");
$snoopy = new Snoopy;
//$Parameters这个是要提交的数组
$Parameters["username"] = "user";
$Parameters["pass"] = "pass";
$file = "/test/test.jpg";
$serviceUrl = "http://www.test.com/fileProcess.php";
$postfiles["image"] = $file; //$filename上传文件相对路径 例如"upload/taoav.jpg";image/jpg
$snoopy->_submit_type = "multipart/form-data"; //设定submit类型
$snoopy->submit($serviceUrl,$Parameters,$postfiles);


$url = "http://www.bkjia.com/ login";

$ch = curl_init();
$header[] = "Content-type: text/xml";//Define content-type as xml
curl_setopt($ch, CURLOPT_URL, $url); / /Define form submission address
curl_setopt($ch, CURLOPT_POST, 1); //Define submission type 1: POST; 0: GET
curl_setopt($ch, CURLOPT_HEADER, 1); //Define whether to display Status header 1: displayed; 0: not displayed
curl_setopt($ch, CURLOPT_HTTPHEADER, $header);//Define the request type
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 0);//Define whether to output directly Return stream
curl_setopt($ch, CURLOPT_POSTFIELDS, $data); //Define the submitted data, here is the XML file
curl_close($ch);//Close

Let’s introduce another case of POST form submission

The code is as follows
Copy code
//First reference this class
include("/data/tools/pooy/Snoopy/Snoopy.class.php" );
$snoopy = new Snoopy;
//$Parameters is the array to be submitted
$Parameters["username"] = "user";
$Parameters[" pass"] = "pass";
$file = "/test/test.jpg";
$serviceUrl = "http://www.test.com/fileProcess.php";
$postfiles["image"] = $file; //$filename relative path to upload file such as "upload/taoav.jpg";image/jpg
$snoopy->_submit_type = "multipart/form-data" ; //Set the submit type
$snoopy->submit($serviceUrl,$Parameters,$postfiles);
http://www.bkjia.com/PHPjc/444618.html
www.bkjia.comtruehttp: //www.bkjia.com/PHPjc/444618.htmlTechArticleThis article will introduce to you a way to use PHP CURL to simulate POST to submit XML data, because the recipient only accepts xml data. I just wrote one and share it with all my friends who are in need...
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