Notice: undefined index.. Error prompt solution_PHP tutorial-PHP Tutorial-php.cn

Notice: undefined index.. Error prompt solution_PHP tutorial

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Release： 2016-07-13 10:55:45

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This sentence is about some problems that will be encountered in PHP development. Looking at this prompt, we all know that the variable is undefined, so let’s solve the Notice: undefined index method.

First, because the variable is undefined, we only need to Find relevant location plus

The code is as follows

代码如下

复制代码

function _get($str){
$val = !empty($_GET[$str]) ? $_GET[$str] : null;
return $val;
}

或

isset($_GET['你的变量'])?$_GET['你的变量']:'';

Copy code

function _get($str){
$val = !empty($_GET[$str]) ? $_GET[$str] : null;

return $val;

代码如下	复制代码
if (!$cfg['debug']) { error_reporting(0); ob_start('ob_gzhandler'); } else { error_reporting(E_ALL ^ E_NOTICE); }

}

isset($_GET['your variable'])?$_GET['your variable']:'';

We only mentioned the usage of get above. The same is true for post. Just change the get above to post.

There is also a global definition method for the program

error_reporting(0); ob_start('ob_gzhandler');

The code is as follows	Copy code
if (!$cfg['debug']) {

} else { error_reporting(E_ALL ^ E_NOTICE);

}

Modify the php.ini configuration file, error_reporting = E_ALL & ~E_NOTICE

Method 2: Add @ before the notice code appears. @ indicates that there is an error in this line or a warning not to output, @$username=$_post['username'];

Note: If you are using global definitions or modifying the php.ini configuration file so that all error prompts will not appear, this will be quite troublesome for development and testing. The best way to use the program is to turn off the error prompts. Set up on the server. http://www.bkjia.com/PHPjc/632213.htmlwww.bkjia.comtruehttp: //www.bkjia.com/PHPjc/632213.htmlTechArticleThis sentence is about some problems that will be encountered in PHP development. Looking at this prompt, we all know that the variable is undefined. Then let’s solve the Notice: undefined index method. 1. This is because the variable is undefined...