Home > Web Front-end > JS Tutorial > Use a simple script to implement a beautiful drop-down menu_javascript skills

Use a simple script to implement a beautiful drop-down menu_javascript skills

WBOY
Release: 2016-05-16 19:23:25
Original
938 people have browsed it

An accidental and boring experiment discovered this way of writing a drop-down menu. The joyful feeling after completing the work is like Archimedes discovering the principle of buoyancy while soaking in the bathtub!

NAME:Stupid CAT Pull-down Menu v1.0
SUPPORT:Ie(√) Firefox(√)
STANDARD:XHTML 1.0 Strict / CSS2.0

Core Style :

Copy code The code is as follows:

html,body{
background:#000000 ;
height:100%;
font-size:12px;
font-family:Arial, Helvetica, sans-serif;
color:#333333;
margin:20px auto;
overflow:hidden;
text-align:center;}
/*menu container menu*/
div#menu{
width:100%;
height:34px;
padding:0px 0px 0px 5px;}
/*First level menu*/
div#menu div{
width:125px;
height:20px;
float:left;
text-transform:capitalize;
background:#cccccc;
padding:5px 0px 0px 0px;
margin:4px 1px 0px 0px;}
/*Secondary menu*/
div #menu div div{
width:125px;
height:20px;
border-bottom:1px #333333 solid;
background:#666666;
margin-top:-4px;
cursor:pointer;
display:none;}
/*Special style in the secondary menu (optional)*/
div#menu div div.div1{
margin-top:3px ;
border-top:1px #333333 solid;}


Core code:
Copy code The code is as follows:

var menuItem=document.getElementById("menu").getElementsByTagName("div");
for(i=0;i menuItem[i].onmouseover=function(){
var subMenu=this.getElementsByTagName("div");
for(j=0;j subMenu[j].style.display="block";
subMenu[j].onmouseover=function(){this.style.background="#999999";this.style.color="# 000000";};
subMenu[j].onmouseout=function(){this.style.background="#666666";this.style.color="#333333";};}
this.style .background="#666666"};
menuItem[i].onmouseout=function(){
var subMenu=this.getElementsByTagName("div");
for(j=0;j subMenu[j].style.display="none";}
this.style.background="#cccccc"};
}

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template