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php数组过滤问题

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Release: 2016-06-23 14:04:41
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假设数组
array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );

我希望只保留 parent 为2的值要怎么做呢?
小弟新人希望大侠帮忙 谢谢!


回复讨论(解决方案)

$a = array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );$t = array_map(function($v) { return array('parent' => $v['parent']); }, $a);/*php 5.2.x 写作$t = array_map(create_function('$v', 'return array("parent" => $v["parent"]);'), $a);*/print_r($t);
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Array
(
[0] => Array
(
[parent] => 1
)

[1] => Array
(
[parent] => 1
)

[2] => Array
(
[parent] => 2
)

)

function intersect2nd($arr1, $arr2, $key)
{
foreach($arr2 as $v) $tmpArr[] = $v[$key];
foreach($arr1 as $k=>$v) if(in_array($v[$key], $tmpArr)) $arr[$k] = $v;
return $arr;
}
$a=array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );
$b=array(array('parent' => 2)); //这个自己编一个类似数组,包含所需key和值就行
$c= intersect2nd($a, $b, 'parent');
var_export($c);

记忆中这是版主唠叨的代码,不敢僭越

PHP code?1234567$a = array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );$t = array_map(function($v) { r……
先谢谢版主

不过不是这样哦,可能我表达的不是很清楚,我是希望保留 parent 的值为2 所在的数组,就是保留这个array('catid' => 21 , 'parent' => 2)。

function intersect2nd($arr1, $arr2, $key)
{
foreach($arr2 as $v) $tmpArr[] = $v[$key];
foreach($arr1 as $k=>$v) if(in_array($v[$key], $tmpArr)) $arr[$k] = $v;
return $arr;
}
$a=arra……
多谢 已经解决了。

显然这不是我的代码,因为不符合我的书写风格

function intersect2nd($arr1, $arr2, $key)
{
foreach($arr2 as $v) $tmpArr[] = $v[$key];
foreach($arr1 as $k=>$v) if(in_array($v[$key], $tmpArr)) $arr[$k] = $v;
return $arr;
}
$a=arra……

不喜欢回调函数的话,可以这么写

$a = array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );foreach($a as $r) {  $t[] = array_intersect_key($r, array('parent' => ''));}
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显然这不是我的代码,因为不符合我的书写风格

引用 2 楼 snmr_com 的回复:function intersect2nd($arr1, $arr2, $key)
{
foreach($arr2 as $v) $tmpArr[] = $v[$key];
foreach($arr1 as $k=>$v) if(in_array($v[$key], $tmpA……

嘿嘿,我说的是思路,我改成自己class里面一个方法用了,现在copy改动后的版本出来而已

不过不是这样哦,可能我表达的不是很清楚,我是希望保留 parent 的值为2 所在的数组,就是保留这个array('catid' => 21 , 'parent' => 2)。 噢,这样写

$a = array(0 => array('catid' => 10 , 'parent' => '1') , 1 => array('catid' => 11 , 'parent' => 1) , array('catid' => 21 , 'parent' => 2) );$t = array_filter($a, function($v) { return $v['parent'] == 2; });print_r($t);
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Array
(
    [2] => Array
        (
            [catid] => 21
            [parent] => 2
        )

)

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