已经定义hint=0为啥还要if(hint=0)

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Release: 2016-06-23 14:01:13
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代码如下:

<?php$xmlDoc = new DOMDocument();$xmlDoc->load("links.xml");$x=$xmlDoc->getElementsByTagName('link');//get the q parameter from URL$q=$_GET["q"];//lookup all links from the xml file if length of q>0if (strlen($q) > 0){$hint="";for($i=0; $i<($x->length); $i++) { $y=$x->item($i)->getElementsByTagName('title'); $z=$x->item($i)->getElementsByTagName('url'); if ($y->item(0)->nodeType==1)  {  //find a link matching the search text  if (stristr($y->item(0)->childNodes->item(0)->nodeValue,$q))   {   if ($hint=="")    {    $hint="<a href='" .     $z->item(0)->childNodes->item(0)->nodeValue .     "' target='_blank'>" .     $y->item(0)->childNodes->item(0)->nodeValue . "</a>";    }   else    {    $hint=$hint . "<br /><a href='" .     $z->item(0)->childNodes->item(0)->nodeValue .     "' target='_blank'>" .     $y->item(0)->childNodes->item(0)->nodeValue . "</a>";    }   }  } }}// Set output to "no suggestion" if no hint were found// or to the correct valuesif ($hint == "") { $response="no suggestion"; }else { $response=$hint; } //output the responseecho $response;?>
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这段代码中:
if ($hint=="")    {    $hint="<a href='" .     $z->item(0)->childNodes->item(0)->nodeValue .     "' target='_blank'>" .     $y->item(0)->childNodes->item(0)->nodeValue . "</a>";    }   else    {    $hint=$hint . "<br /><a href='" .     $z->item(0)->childNodes->item(0)->nodeValue .     "' target='_blank'>" .     $y->item(0)->childNodes->item(0)->nodeValue . "</a>";    }
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问题1:之前不是已经定义$hint=0了,为啥还要if ($hint=="")?
问题2:如题$hint不=0,后面的代码在执行什么?


回复讨论(解决方案)

where $hint=0 ?

声明$hini=“” 是为了存储用的,第一次循环的时候$hini是没有值的,但是第二次循环的时候就有了啊

where $hint=0 ?

$hint=""
是 ,不是0,但是为了方便我说成是0了

$hint="";是在for循环之外定义的;在$i = 0的时候$hint是空的字符串会进入到if ($hint=="")判断中 但循环加1时也就是$i = 1时此时的$hint已经不再是空的字符串;这个判断就是为了区别第一次循环

$hint="";是在for循环之外定义的;在$i = 0的时候$hint是空的字符串会进入到if ($hint=="")判断中 但循环加1时也就是$i = 1时此时的$hint已经不再是空的字符串;这个判断就是为了区别第一次循环
其实可以不用判断的

这是用来判断是不是第一行,不是第一行的话前面加
换行
其实列表换行这种事,交给CSS来做比较好,不用加
,也就省去这样判断了。

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