preg_replace_callback函数-PHP Tutorial-php.cn

preg_replace_callback函数

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Release： 2016-06-23 14:00:58

Original

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$val = preg_replace("/\[([^\[\]]*)\]/eis", "'.'.str_replace('$','\$','\\1')", $val);

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这一句用preg_replace_callback函数怎么改写呢求指教下

回复讨论(解决方案)

$val = preg_replace_callback("/\[([^\[\]]*)\]/eis", function($match){ return str_replace('$','\$',$match)}, $val);

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$val = preg_replace_callback(        '/\[([^\[\]]*)\]/is',        function ($matches) {            return '.'.str_replace('$','\$',$matches[1]);        },        $val    );echo $val;

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同理这个呢

$out = "<?php \n" . '$k = ' . preg_replace("/(\'\\$[^,]+)/e" , "stripslashes(trim('\\1','\''));", var_export($t, true)) . ";\n";

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求说一下改的基本思想还是不太懂谢谢了

同理这个呢

$out = "<?php \n" . '$k = ' . preg_replace("/(\'\\$[^,]+)/e" , "stripslashes(trim('\\1','\''));", var_export($t, true)) . ";\n";

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求说一下改的基本思想还是不太懂谢谢了

这个已改好依葫芦画瓢的 = =

$out = "<?php \n" . '$k = ' . preg_replace_callback("/(\'\\$[^,]+)/" , function($ro) { return stripslashes(trim($ro[1],'\''));}, var_export($t, true)) . ";\n";

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最后一处了这里中间的代码 include哪一行不清楚怎么改

$pattern = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/s';$replacement = "'{include file='.strtolower('\\1'). '}'";$source = preg_replace_callback($pattern, $replacement, $source);

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最后一处了这里中间的代码 include哪一行不清楚怎么改

$pattern = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/s';$replacement = "'{include file='.strtolower('\\1'). '}'";$source = preg_replace_callback($pattern, $replacement, $source);

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还是一样的也还是一字符串啊还是原来的方式就行了

最后一处了这里中间的代码 include哪一行不清楚怎么改

$pattern = '/<!--\s#BeginLibraryItem\s\"\/(.*?)\"\s-->.*?<!--\s#EndLibraryItem\s-->/s';$replacement = "'{include file='.strtolower('\\1'). '}'";$source = preg_replace_callback($pattern, $replacement, $source);

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还是一样的也还是一字符串啊还是原来的方式就行了

主要是这一会不会改了，可以帮我改改看么就最短的这句

$replacement = "'{include file='.strtolower('\\1'). '}'";

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非常感谢

$replacement = function ($matches) { return '{include file='.strtolower($matches[1]). '}';};