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php获取url里指定位置的参数

WBOY
Release: 2016-06-23 13:36:07
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php获取url里指定位置的参数,因为url后的参数是变动的。怎样获取呢?如www.xxx.com?act=game&st=play&b1=1&round=1,有时候这个url会输出成www.xxx.com?act=game&st=play&b2=2&round=1,其中的b1、b2、b3.。。。一直到b15.怎样获取这个url输出的b1还是b2还是其他及他的值呢


回复讨论(解决方案)

把查询字符串输出成一个数组不就行了

用名字访问

$s = 'www.xxx.com?act=game&st=play&b1=1&round=1';parse_str(@array_pop(explode('?', $s)), $a);print_r($a);$s = 'www.xxx.com?act=game&st=play&b2=2&round=1';parse_str(@array_pop(explode('?', $s)), $a);print_r($a);
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Array
(
    [act] => game
    [st] => play
     [b1] => 1
    [round] => 1
)
Array
(
    [act] => game
    [st] => play
     [b2] => 2
    [round] => 1
)

parse_str
http://www.w3school.com.cn/php/func_string_parse_str.asp

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