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TinkPHP+EasyUI,json怎么条件查询数据库?先谢谢了!

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Release: 2016-06-20 12:43:37
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href:'__URL__/sblog/id/'+idd,
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//$json为NULL输出模板。为1时输出列表数据到前端,格式为Json	public function sblog($json=NULL,$id=NULL){		if(!is_int((int)$json)){			$json = NULL;		}                //dump($id);  这里能显示ID为16		if($json==1){			$sblog = M('Sbly_table');			//$id = intval($id);			//$info = $sblog->order('id desc')->where('lj_sbid='.$id)->select();			$info = $sblog->order('id desc')->select();			$new_info = array();			foreach($info as $t){				if($t['lj_ly_zt']==1){					$t['lj_ly_zt'] = '开启';				}else{					$t['lj_ly_zt'] = '关闭';				}				$new_info[] = $t;			}			echo json_encode($new_info);			unset($sblog,$info,$new_info);		}else{			$this->display();		}		unset($Public);    }
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$json=1时, 输出如下3条内容:

[{"id":"38","user_id":"1","title":"001","lj_sbid":"16"},{"id":"36","user_id":"1","title":"002","lj_sbid":"18"},
{"id":"34","user_id":"1","title":"003","lj_sbid":"17"}]

<script language="javascript">$(function(){	var th = $(".top").height();	th = 111-th;	var wh = $(window).height()-th;		$("#Sblog").datagrid({		//title:'列表',			height:wh,		autoRowHeight:true,		singleSelect:true,		striped:true,		rownumbers:true, //显示行号		method:'get',		url:'__ACTION__/json/1, //加载的URL 		pagination:true,//显示分页  		pageSize:5,//分页大小 		pageList:[5,10,15,20],//每页的个数		//fit:true,//自动补全		fitColumns:true,		nowrap:Number('{$TC.config.DATA_NOWRAP}'),		onBeforeLoad: function () {  					},		toolbar:[ //工具条 		{			iconCls: 'icon-reload',			text : '刷新',			handler: function(){ //回调函数  				$("#Sblog").datagrid('reload');			}		}		],		columns:[[   		    {field:'lj_sbid',title:'ID',width:50,align:'center'},			{field:'title',title:'名称',width:250},			{field:'lj_ly_zt',title:'状态',width:100},		]]	});});</script><div class="con" id="SblogCon" onselectstart="return false;" style="-moz-user-select:none;">	<table id="Sblog"></table></div><div id="addSblog"></div>
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前端处理后能正确显示3行数据,但是我只想要显示lj_sbid为16的数据,
$info = $sblog->order('id desc')->where('lj_sbid=16')->select();
这样能正确显示lj_sbid为16的一条数据,但是这样:
$info = $sblog->order('id desc')->where('lj_sbid='.$id)->select();
又不能输出?该怎么写才对?先谢谢大家了


回复讨论(解决方案)

理论上写的没什么问题,你可以尝试输出下$id是什么值

order应该在where 后边

$id能输出16,到底是哪里错误呢?

你要的不是$id的值

模板sql语句 语法有问题

你要的不是$id的值

模板sql语句 语法有问题



$id只是条件,语法错误在哪里?请高手指点一下,谢谢主!

dump($id); 贴出结果

dump($id);  

输出:
string(2) "16"

你不是用 EasyUI 吗?
string(2) "16" 在哪里看到的?

TinkPHP+EasyUI  

sblog.htm模板输出的 

用 Volist标签老显示载入中......,改用Foreach标签就OK了

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