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PHP中区分null和false的方法

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Release: 2016-06-20 12:34:24
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echo json_encode(0)."<br/>";     //输出"0"echo json_encode(null)."<br/>";    //输出"null"echo json_encode(false)."<br/>";    //输出"false"//被json_encode转码后,类型就是string//做判断就得用如下例子:if(json_encode(null) =="null"){    echo 1;}else{    echo 2;}//输出1
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区分 null和 false意义很大,因为在数据库交互中,如select,查询结果是空则返回 null, 而出错则返回 false。

区分了 null 和 false,才可以更加好地支持 事务


Thinkphp的query方法数据库交互的错误判断:

$model =new Model();$order ="select * from asd where seatNm=1";$res =$model->query($order);if(json_encode($res) !="false" && $res[0] ==null){    //结果集为空    echo 123;}else if(json_encode($res) =="false"){    //查询出错    echo 789;}else{     //返回非空结果集    echo 456;}
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ps:我用的是tp3.1,不知道3.2是不是有更好的判断机制出现



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