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php+mysql 判断记录位置

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Release: 2016-06-20 12:28:48
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ID        Catid        Order
1        1                1
2        1                5
3        2                3
4        1                2
5        2                15
7        1                11
8        1                9
...
152       1            155
153        1            143

我需要的是根据一个ID,算出这个ID是当前CATID下的第几条记录

比如 给的 ID 是 7 对应的Catid是1 。 SQL语句就是: 

SELECT * FROM `news_list` WHERE `TId` =1ORDER BY `order` ASC LIMIT x , 30
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因为根据order排序,而且数据比较多。

需要解决的问题是:
比如给个ID=7 , 根据ID所属的Catid,计算出获取的结果中此ID的位置。(7是第4条记录)

希望大神们帮忙。

ps:数据量大,不能先读出满足条件的所有记录,再判断。

我的回答如下:

set @i :=0;SELECT @i :=@i+1 as num,news_list.* FROM `news_list` WHERE `catid` =1ORDER BY `order` ASC LIMIT 0 , 30
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