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把历次都要执行的部分抽出来

WBOY
Release: 2016-06-13 12:53:10
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把每次都要执行的部分抽出来
php中,共有3个函数,其中绝大分数是相同的。如何能更科学的变成一个函数,从而搞效率。
方法一:将此3个函数变成一个,怎么实现呢?
方法二:奖此3个函数的执行体,就是输出的部分公共部分,单独做个函数。如何实现呢?????

function wc1($sql){<br />
	<br />
	$tb='';<br />
		$showArr=array();<br />
		$q=$this->getAll3($sql);<br />
		while ($r=$q->fetch_array(MYSQLI_USE_RESULT)) {<br />
				$tb.='<tr><td>'.$r["number"].'</td>';<br />
				$tb.=isset($this->show["customer"])?'<td>'.$r["customer"].'</td>':NULL;<br />
				$tb.=isset($this->show["orderNo"])?'<td>'.$r["orderNo"].'</td>':NULL;<br />
<br />
<br />
		}<br />
		return $tb;		<br />
}<br />
function wc2($sql){<br />
	<br />
	$tb='';<br />
		$showArr=array();<br />
		$q=$this->getAll3($sql);<br />
		while ($r=$q->fetch_array(MYSQLI_USE_RESULT)) {<br />
				$tb.='<tr><td>'.$r["number"].'</td>';<br />
				$tb.=isset($this->show["customer"])?'<td>'.$r["customer"].'</td>':NULL;<br />
				$tb.=isset($this->show["orderNo"])?'<td>'.$r["orderNo"].'</td>':NULL;<br />
				$tb.=isset($this->show["name"])?'<td>'.$r["name"].'</td>':NULL;<br />
				$tb.=isset($this->show["wc"])?'<td>'.$r["wc"].'</td>':NULL;//----------------此处有变化<br />
<br />
		}<br />
		return $tb;		<br />
}<br />
function wc3($sql){<br />
	<br />
	$tb='';<br />
		$showArr=array();<br />
		$q=$this->getAll3($sql);<br />
		while ($r=$q->fetch_array(MYSQLI_USE_RESULT)) {<br />
				$tb.='<tr><td>'.$r["number"].'</td>';<br />
				$tb.=isset($this->show["customer"])?'<td>'.$r["customer"].'</td>':NULL;<br />
				$tb.=isset($this->show["orderNo"])?'<td>'.$r["orderNo"].'</td>':NULL;<br />
				$tb.=isset($this->show["name"])?'<td>'.$r["name"].'</td>':NULL;<br />
				$tb.=isset($this->show["fsaww"])?'<td>'.$r["sfs3"].'</td>':NULL;//----------------此处有变化<br />
<br />
		}<br />
		return $tb;		<br />
}
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------解决方案--------------------
function wc($sql){<br />
  $tb='';<br />
  $showArr=array();<br />
  $q=$this->getAll3($sql);<br />
  $dict = array('fsaww' => 'sfs3'); //这里是对照表<br />
  while ($r=$q->fetch_array(MYSQLI_USE_RESULT)) {<br />
    $tb.='<tr><td>'.$r["number"].'</td>';<br />
    foreach($this->show as $k) {<br />
      if(isset($dict[$k])) $k = $dict[$k];<br />
      $tb.='<td>'.$r[$k].'</td>';<br />
    }<br />
  }<br />
  return $tb;        <br />
}
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------解决方案--------------------

<?php <br />
function wc1($sql, $assoc = array()){<br>
<br>
	$tb='';<br>
	$showArr = array();<br>
	$q=$this->getAll3($sql);<br>
	while ($r=$q->fetch_array(MYSQLI_USE_RESULT)) {<br>
		$tb.='<tr>
<td>'.$r["number"].'</td>';<br>
		if(count($assoc)){<br>
			foreach($keys as $k => $v){<br>
				$tb .= isset($this->show[$k]) ?'<td>'.$r[$v].'</td>':NULL;<br>
			}<br>
		}<br>
	}<br>
	return $tb;<br>
}<br>
<br>
wc1($sql, array('customer' => 'customer', 'orderNo' => 'orderNo'));<br>
wc1($sql, array('customer' => 'customer', 'orderNo' => 'orderNo', 'name' => 'name', 'wc' => 'wc'));<br>
wc1($sql, array('customer' => 'customer', 'orderNo' => 'orderNo', 'name' => 'name', 'fsaww' => 'sfs3')); <div class="clear">
                 
              
              
        
            </div>
</tr>
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